As a product of its prime factors: 2*3*3*5*7 = 630
It is: 2*3*3*5*7 = 630
2 x 3 x 3 x 5 x 7 = 630
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2
1 and 630
As a product of its prime factors: 2*3*3*5*7 = 630
Add 149, 151, 163 and 167 together.
The GCF of 735 and 630 is 105. To find the GCF of two numbers, you first have to split them into their prime factors. In this case, 735 and 630 can be broken down as follows: 735 = 3x5x7x7 630 = 2x3x3x5x7 The next step is to identify any common prime factors. In this case, both numbers have prime factors of one 3, one 5 and one 7. To find the HCF, we multiply these factors together: 3x5x7 = 105 Thus the GCF of 735 and 630 is 105.
It is: 2*3*3*5*7 = 630
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
2 x 3 x 3 x 5 x 7 = 630
2*3*3*5*7
630
It is: 630 by finding the prime factors of the given numbers
It is: 630 by multiplying the highest prime factors of both numbers
The prime factors of 630 are: 2, 3, 5, 7