The prime factorization of 14 is 2 x 7.
The easiest way to do this is to split the numbers down into their prime factors: 14 = 2x7 20 = 2x2x5 The next step is to spot any common prime factors. In this case both numbers have a 2 as a prime factor. Therefore, the HCF of 14 and 20 is 2.
13 is prime 14=2x7, 2 factors 15=3x5, 2 factors 16=24, 4 factors 17 is prime 18=2x32, 3 factors 19 is prime So the answer is 3 (14, 15 and 16)
A multiple of 7 is any number that can divide evenly into 7. The easy way to find multiples of 7 is to multiply 7 by each integer in turn (1x7, 2x7, 3x7, 4x7, and so on). Using this method, you can quickly work out what the multiples of 7 between 15 and 50 are. They are: 21, 28, 35, 42 and 49.
Any numbers that don't have common prime factors will do; for example, 23 and 32; 2x3 and 5x7, 3x5 and 2x7, etc.Any two consecutive numbers will have no common factor, for example, 8 and 9 (the first example I gave above), or 100 and 101. However, in the second example, 101 is not a composite number.
9^1x7^x9^2x7^1x9^1
The final answer is 112.
2 x 7 + 5 = 19
I'm going to assume the polynomial in question is 2x7+(3-2x3)+(5x8-4x) Expanding out the polynomial: 2x7+3-2x3+5x8-4x Order the terms by powers of x: 5x8+2x7-2x3-4x+3 Since 8 is the highest power of x, the degree of the polynomial is 8.
If I do your homework for you, you will fail your test.
19 - 2*7 + 98/14 = 12.
2 4/7 = (2x7+4)/7 = 18/7
The LCM (Least Common Multiple) of 2x7 and 4x9 is 36x63.
14
14
313
2x7 = 14 x7 = 7 3x7 = 3*7 = 21