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The sum of any two successive triangular number is a square number.

The nth triangular number is n(n+1)/2 = (n2 +n)/2

The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2

Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2

This is easy to visualise. For example T3 + t4 = 42

[T3, the 3th triangular number represented by X,

t4, the 4th triangular number represented by x]

XXX_____x

XX_____xx

X_____xxx

_____xxxx

Bring them together and you have:

XXXx

XXxx

Xxxx

xxxx

The sum of any two successive triangular number is a square number.

The nth triangular number is n(n+1)/2 = (n2 +n)/2

The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2

Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2

This is easy to visualise. For example T3 + t4 = 42

[T3, the 3th triangular number represented by X,

t4, the 4th triangular number represented by x]

XXX_____x

XX_____xx

X_____xxx

_____xxxx

Bring them together and you have:

XXXx

XXxx

Xxxx

xxxx

The sum of any two successive triangular number is a square number.

The nth triangular number is n(n+1)/2 = (n2 +n)/2

The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2

Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2

This is easy to visualise. For example T3 + t4 = 42

[T3, the 3th triangular number represented by X,

t4, the 4th triangular number represented by x]

XXX_____x

XX_____xx

X_____xxx

_____xxxx

Bring them together and you have:

XXXx

XXxx

Xxxx

xxxx

The sum of any two successive triangular number is a square number.

The nth triangular number is n(n+1)/2 = (n2 +n)/2

The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2

Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2

This is easy to visualise. For example T3 + t4 = 42

[T3, the 3th triangular number represented by X,

t4, the 4th triangular number represented by x]

XXX_____x

XX_____xx

X_____xxx

_____xxxx

Bring them together and you have:

XXXx

XXxx

Xxxx

xxxx

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Wiki User

βˆ™ 11y ago

The sum of any two successive triangular number is a square number.

The nth triangular number is n(n+1)/2 = (n2 +n)/2

The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2

Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2

This is easy to visualise. For example T3 + t4 = 42

[T3, the 3th triangular number represented by X,

t4, the 4th triangular number represented by x]

XXX_____x

XX_____xx

X_____xxx

_____xxxx

Bring them together and you have:

XXXx

XXxx

Xxxx

xxxx

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Q: How do your use triangular numbers to make square numbers?
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What are the real numbers that is not a whole number?

Real numbers are all numbers which do not contain "i", when "i" represents the square root of -1. All numbers which do contain "i" are "imaginary numbers" and are not real numbers. This means that all numbers you'd ordinarily use are real numbers - all the counting numbers (integers) and all decimals are real numbers. So in answer to your question, all the real numbers that are not whole numbers are all the decimal numbers - including irrational decimals such as pi.


How do you check if a number is a triangular number?

you need to use this formula: n(n+1) T=--------- 2 So number times (number + 1) divided by 2. If the number you get is the same number as n its a triangular number. if it isn't well it isn't a triangular number.


There are numbers from 1 to n. they have to be inverted as n to 1 . How many moves are required if only two consecutive numbers are stampled at a time?

There are (n2 - n) / 2 moves required.I am not aware that "stampled" is a word beyond a cross between stampede and trample, but I believe you wish to reverse the order of numbers from 1 to n where only two consecutive numbers can be swapped per step.This process will show a pattern of triangular numbers. For example:Let us suppose there are 3 numbers 1,2,3: To move the last (highest) number to the first place requires 2 steps. The second highest number is now in the last place. To move it to the second place requires 1 step. Finished. Total = 3 steps.Or:If there are 4 numbers, i.e. 1,2,3,4:3 steps + 2 steps + 1 step = 6 steps total. We know it is only 3 steps more than the last example because once we have moved the 4 to the first place we then simply have to do the above again (rearrange the 1,2,3, to 3,2,1).So you can see that the number of steps are all triangular numbers.A triangular number is calculated by n(n+1) / 2. So we can use this formula, but we need to alter it because the number of steps are for the previous triangular number. E.g. Where there are 4 numbers we have to do 1+2+3 steps to reorder it (see above).Therefore if we make our formula (n - 1) n / 2 = (n2 - n) / 2 then this will work.


What are similarities and differences between Mayan number system and Hindu Arabic number system?

Both make use of a zero symbol but Mayan numbers have 20 as a base whereas Hindu-Arabic numbers have 10 as a base.


What is the units digit of the 5857th triangular number.?

The nth triangular number is given by ½ × n × (n+1)→ the 5857th triangular number is ½ × 5857 × 5858 = 17,155,153, so its units digit is a 3.------------------------------------------------------------Alternatively,If you look at the units digits of the first 20 triangular numbers they are {1, 3, 6, 0, 5, 1, 8, 6, 5, 5, 6, 8, 1, 5, 0, 6, 3, 1, 0, 0}At this stage, as we are only concerned with the units digit, as we now have a 0 for the units digit, when 21 is added it is the same as adding 1 to 0 to give a 1, for the 22nd triangular number, we are adding 2 to the 1 to give 3, and so on - the sequence of 20 digits is repeating.To find the units digit of the nth triangular number, find the remainder of n divided by 20 and its units digit will be that digit in the sequence (if the remainder is 0, use the 20th number). To find the remainder when divided by 20 is very simple by looking at only the tens digit and the units digit:If the tens digit is even (ie one of {0, 2, 4, 6, 8}), the remainder is the units digitIf the tens digit is odd (ie one of {1, 3, 5, 7, 9}), the remainder is the units digit + 10.5857 ÷ 20 = ... remainder 17; the 17th digit of the above sequence is a 3, so the units digit of the 5857th triangular number is a 3.This trick can be used for much larger triangular numbers which calculators cannot calculate exactly using the above formula. eg the units digit of the 1234567890123456789th triangular number is... 1234567890123456789 ÷ 20 = .... remainder 9, so this triangular number's units digit is the 9th digit of the above sequence which is a 5.

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