It depends on the volume of the room.
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
It takes 8.34 BTU to heat 1 gallon of water 1 degree F. Take 8.34 BTU times number of gallons to determine energy needed to raise pool 1 degree F. Then multiply by how many degrees you need to raise the temperate of the current pool temperature to the desired temperature. Example: 8.34 * 30,000 gal = 250,200 BTU need to raise temperature 1 degree F Next multiple by the number of degrees to warm, say the pool is 55 F. 80F - 55F = 25F. 250,200 BTU * 25 F = 6.255 million BTUs to heat the pool to 80 F. This does not take into account the loss of energy to the surroundings but gives you a starting point to determine the energy needed to heat a mass of water.
It will vary on the room type and construction. However you can assume you want 10-15 watts of energy per square ft. That would mean you want 2500-3750 watts total, which would be 8,500 - 12,750 BTU's (3.4 BTUs/Watt).References:How_many_square_feet_does_a_5000_BTU_heater_heathttp://www.diychatroom.com/f18/btus-watts-35066/
13000
To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.
6,520 Btus
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.
That will completely depend on how much water there is.
25
2250
It depends on the volume of the room.
To raise 1 pound of ice from 32°F to water at 32°F it requires 144 BTUs. Since you have 50 pounds of ice, you would need 50 * 144 BTUs to raise the ice to water at 32°F. To further raise the water from 32°F to 160°F, you would need an additional amount of BTUs based on the specific heat capacity of water.
BTUs, or British Thermal Units, measure the amount of heat energy required to raise the temperature of one pound of water by one degree Fahrenheit. The formula to calculate BTUs is: BTUs = weight of water (in pounds) x temperature change (in degrees Fahrenheit) x 1. Alternatively, the formula can be expressed as: BTUs = (Flow rate in gallons per minute x change in temperature in degrees Fahrenheit) / 500.
To calculate the BTUs required to raise the temperature of water, you can use the formula: BTUs = (pounds of water) x (temperature change in °F) x (1 BTU). For 15 pounds of water going from 100°F to 120°F, the calculation would be: BTUs = 15 pounds x 20°F x 1 BTU = 300 BTUs.
It takes 180 BTUs to raise 1 pound of water from 32 degrees Fahrenheit to 212 degrees Fahrenheit to convert it completely into steam. This change in temperature includes heating the water from its freezing point to boiling point, then undergoing phase change from liquid to gas.