NOT AN ANSWER:
More acceptable combinations:
1231 3213 2321
More unacceptable combinations:
1112 2222 3113
Thanks.
The repeated factor of 102 is 10.
The repeated prime factor is 2.
It is 33.33... repeated %.
.23 repeated as a fraction is 23/99
0.453 repeated as a fraction = 453/999
Assuming the digits are not repeated, there are four combinations:123, 124, 134 and 234.
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
Letters - 26Numbers - 10Total chacters - 36If characters can be repeated (QQ and 44 are acceptable): 36 x 36 = 1,296If characters can't be repeated (GG and 99 not acceptable): 36 x 35 = 1,260If characters can't be repeated and the sequencedoesn't matter (X7 and 7X are considered to be the same): 630
10 to the third assuming zero is included and can lead, otherwise 9 to the third, ie 729. This all assumes that you are talking about 3-digit numbers. * * * * * No. That may be the number of permutations but those are different from combinations. In a combiation, the order of the digits does not matter so that 123 is the same as 132 or 213 etc. With repetition, there are 210 COMBINATIONS, including one that is {0,0,0}.
If you have 4 positions, each of which can hold any of the ten digits, you have 10 to the power 4 combinations. If you can have only 4 different digits, you have 4 to the power 4 different combinations.
be repeated until performace is at an acceptable level
If no digit can be repeated then there are 5 combinations, abcd, abce, abde, acde and bcde. If you regard abdc as different from abcd then each of the 5 basic sets could be arranged 24 ways and the total would be 120 combinations.
9