Best Answer

Letters - 26

Numbers - 10

Total chacters - 36

If characters can be repeated (QQ and 44 are acceptable): 36 x 36 = 1,296

If characters can't be repeated (GG and 99 not acceptable): 36 x 35 = 1,260

If characters can't be repeated and the sequence

doesn't matter (X7 and 7X are considered to be the same): 630

Q: How many possible alpha numeric combinations using upper case letters and numbers for two chacters?

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it is 26

26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336

If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.

If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.

Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.

Related questions

it is 26

We can use 36 characters for each of the slots in the combination. Therefore, we have 36^11 possible combinations, or 131,621,703,842,267,136 combinations.

87400 combinations

26x26x26x10x10x10 = 17,576,000

im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.

There are 167960 combinations.

26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336

If the numbers contain zeros, the total number of combinations is 10,000. You can work this out easily logically: For ten single-digit numbers (0,1,2,3,4,5,6,7,8,9) then there are 10 possible 'combinations' For numbers with 2 digits then for each possible digit in the 10s column (e.g. in the 20s range) there are another 10 possible combinations (20,21,22,23,24,25,26,27, 28,29). As there are 10 possible ranges (single digits, teens, twenties, thirties etc) there will be 10 X 10 or 100 possible combinations. using the same logic, for three digits, there will be 10 X 10 X 10 or 1000 digits. And for 4 digits there will be 10 x 10 x 10 x 10 = 10,000 possible combinations. So for a number, say, with x digits, the total number of combinations of those digits will be 10 x 10 x 10..... etc with x numbers of 10s in the calculation. You can find out the number of combinations of any set of letters or numbers in the same way. as an example, to find out, say, the possible combinations of letters in the alphabet of 26 letters, then using the same method this can be given as 26 x 26 x 26 x 26............. with 26 '26's' in a row multiplied together. This gives the staggering amount of approximately 615612 followed by 31 zeros.

Just 1.

If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.

If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.

Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.