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The only number with a 6 between 1 and 9 is 6.
Between 10 and 99, every number that ends in a 6 or is in the sixties will have a 6 in it. The former category has 9 numbers in it, the latter 10, but they overlap at 66 so there are 18 numbers total in the range.
Fromm 100 to 999, the number must have a 6 in either the ones, tens, or hundreds digit. 90 numbers have a 6 in the ones place, 90 again in the tens place, and 100 in the hundreds place. NOT including the number 666, there are 8 overlaps that have 6 in both the ones and tens place, 9 with 6 in the ones and hundreds place, and 9 with 6 in the tens and hundreds place. Finally, the number 666 was counted an extra two time. Subtracting all the double/triple appearances, there are 252 numbers with a 6 in this range.
Finally, add up all these ranges to get that there are 271 numbers numbers with the digit 6 in this range.
What else can I help you with?
How many 1 digits are in 100 to 999?
There are 2700 digits.
How many whole numbers between 999 and 9999?
If by "between" you mean "between but not including", then the answer is 9999 - 999 - 1 = 8999.If on the other hand, you mean to include both 9999 and 999, then the answer is 9999 - 999 + 1 = 9001.
What is 1 999 999 rounded to the nearest tens?
0
How many significant digits 0.12?
Two of them which are 1 and 2
What are the factors of 999?
1, 3, 9, 27, 37, 111, 333, 999
How many 1 digits are in 100 to 999?
There are 2700 digits.
how many digits are there number which is the sum of 999 and 1?
It is 4 and 1,000
How many strings of three the same digits have exactly three digits that are 9s?
Only 1 exists, and it is "999"
How many digits in between 1 and 1000?
There are 999 numbers between 1 and 1000, which includes all the integers from 1 to 999. If you're asking about the count of individual digits used in writing these numbers, they collectively comprise a total of 2887 digits. This is calculated by considering the number of digits in one-digit (1-9), two-digit (10-99), and three-digit numbers (100-999).
How many whole numbers have exactly 4 digits?
9000 of them. All of the numbers 1 thru 9999 EXCEPT 1 thru 999. 9999 - 999 = 9000.
How many whole numbers have exactly three digits how did you find that out and tell me why that's the answer?
Assuming that 001, 080, etc are not allowed (that is a leading zero or two is not permitted), the smallest number with exactly three digits is 100. The largest number with exactly three digits is 999. So there are 999 - 100 + 1 = 900 numbers with exactly three digits.
How many digits are there in the numbers 1-10000?
10001
From 1000-9999 how many 4 digit whole numbers are there in all?
Well, let's see now . . .-- If you were to count from 1 to 9,999 you would count 9,999 numbers.-- The first 999 of them would have less than 4 digits.-- So (9,999 - 999) = 9,000 of them would have 4 digits.
How many digits 1 through1000?
2893 digits in all, made up as follows: 9 1-digit numbers (1 to 9) = 1*9 = 9 digits 90 2-digit numbers (10 to 99) = 2*90 = 180 digits 900 3-digit numbers (100 to 999) = 3*900 = 270 digit 1 4-digit number (1000) = 4*1 = 4 digits
How many digits are there in the numbers 1 - 1000?
-999
How many prime numbers are there whose square has 5 or 6 digits?
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
How many digits are used to print from 1 to 11521?
To find the total number of digits used to print the numbers from 1 to 11,521, we can break it down by the number of digits in each range. From 1 to 9 (9 numbers) uses 9 digits, from 10 to 99 (90 numbers) uses 180 digits, from 100 to 999 (900 numbers) uses 2,700 digits, and from 1,000 to 11,521 (10,522 numbers) uses 42,088 digits. Adding these together, the total is 9 + 180 + 2,700 + 42,088 = 44,977 digits.
