There are 19 two-digit positive integers greater than 60.
62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98
Edit: Since you didn't specify greater than 60 up to 100, the answer to your question as written is infinite.
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To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.
All the even numbers greater than 2 are composite.
The set of positive odd integers.
There are 80 positive integers from 1 to 80.Half of them are even, the other half are odd.So there are 40 even integers from 1 to 80.2, 4, 6, and 8 have only 1 digit.All the rest have 2 digits.So the answer is (40 - 4) = 36 .However, as the question asked "less than 80" we can not include 80 and so the answer is 35.
Positive. The product of even numbers of negative integers is always positive, whereas the product of odd nummbers of negative integers is always negative.