To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.
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10*9*8=720
9*9*8*7 = 4536
There are 870 such numbers.
1,2,3,4,5,6,7,8,9,10 all the way thru 1000.
Using Gauss's method, 1+2+3...1000= 500x1001=500500 Answer:500500