Oh, that's a wonderful question! To represent decimal numbers up to 1 million in hexadecimal, you would need about 4 hex digits. Hexadecimal is base 16, so each digit can represent 16 different values (0-9 and A-F), making it an efficient way to represent large numbers in a compact form. Just imagine those beautiful hex digits coming together like little puzzle pieces to create the number 1 million - what a happy little number!
how many bits are needed to represent decimal values ranging from 0 to 12,500?
Yes, 1000000 or 1,000,000 represents 1 million in numbers
1.650 million in numbers is written as 1,650,000. This is the standard way to represent one million six hundred fifty thousand in numerical form. The comma is used to separate the thousands, millions, billions, etc., making it easier to read and understand large numbers.
15,000,000
Oh, dude, you're hitting me with the big numbers. So, 3085 thousands is basically just 3085 with three zeros tacked on, right? So, in decimal form, that would be 3.085 million. Easy peasy, lemon squeezy.
Seven will be more than enough.
1 million < 165 so 6 digits would be enough.
5 will be sufficient.
how many bits are needed to represent decimal values ranging from 0 to 12,500?
The answer depends on the degree of precision. If only integers are to be represented, then 6 digits would be enough because 165 = 1,048,576 is bigger than a million.
The previous number!
0xff = 16 x 15 + 15 = 255 The letters A-F are used to represent the decimal numbers 10-15 (respectively) which are required to be held in one hexadecimal digit.
Decimal numbers are real numbers. In C and C++ we use the float, double and long double data types to represent real numbers.
No, there is no smallest decimal number. Decimal numbers represent real numbers and between any two real numbers there are infinitely many other real numbers. So, there are infinitely many decimal numbers between 0 and your 1.21: each one will be smaller than 1.21
No, there is no smallest decimal number. Decimal numbers represent real numbers and between any two real numbers there are infinitely many other real numbers. So, there are infinitely many decimal numbers between 0 and your 1.02: each one will be smaller than 1.02
To consider the difference between straight binary and BCD, the binary numbers need to be split up into 4 binary digits (bits) starting from the units. In 4 bits there are 16 possible values from 0000 to 1111 (0 to 15). In straight binary all of these possible combinations are used, thus: 4 bits can represent the decimal numbers 0-15 8 bits can represent the decimal numbers 0-255 12 bits can represent the decimal numbers 0-4095 16 bits can represent the decimal numbers 0-65535 etc In arithmetic, all combinations of bits are used, thus: 0000 1001 + 0001 = 0000 1010 In BCD or Binary Coded Decimal, only the representations of the decimal numbers 0-9 are used (that is 0000 to 1001 in binary), and the 4-bits (nybbles) are read as decimal digits, thus: 4 bits can represent the decimal digits 0-9 8 bits can represent the decimal digits 0-99 12 bits can represent the decimal digits 0-999 16 bits can represent the decimal digits 0-9999 In arithmetic, only the representations of decimal numbers are used, thus: 0000 1001 + 0001 = 0001 0000 When BCD is used each half of a byte is read directly as a decimal digit. BCD is obviously inefficient as storage (for large numbers) as each nybble is only holding 3/8 of the possible numbers, however, it is sometimes easier and quicker to work with decimal digits (for example when there is lots of display of counting numbers to do there is less binary to decimal conversion needing to be done).
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.