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3000 and 6000 both have 3 0's, so they are out. The numbers between them all start with 3, 4, or 5, followed by 3 digits. There are 9 possible digits for the hundreds place, which leaves 8 for the tens and 7 for the units digit. The answer is therefore 3 x 9 x 8 x 7 = 1512

Answer 1

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There are 4 possible first digits, 9 possible second digits, 8 possible third digits and 7 possible 4 digits, making a total of 4 x 9 x 8 x 7 = 2016.

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