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3000 and 6000 both have 3 0's, so they are out. The numbers between them all start with 3, 4, or 5, followed by 3 digits. There are 9 possible digits for the hundreds place, which leaves 8 for the tens and 7 for the units digit. The answer is therefore 3 x 9 x 8 x 7 = 1512

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There are 4 possible first digits, 9 possible second digits, 8 possible third digits and 7 possible 4 digits, making a total of 4 x 9 x 8 x 7 = 2016.

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Q: How many integers are there between 3000 and 6000 in which no digit is repeated?
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Related questions

How many four-digit numbers are there between 500 and 3000?

If you include the number 3,000, there are exactly 2,001 4-digit numbers between 500 and 3000.


What is the sum of the integers between 1 and 3000?

Between 1 and 3000, ie the sum of 2, 3, , ... , 2999 is 4498499


How many four digit numders are there between 999 and 3000?

3000-999=2001.


What are the cubed numbers between 2000 and 3000?

The integers with cubed values between 2000 and 3000 are: 133 = 2197 143 = 2744


How many four digit no are there between 999 and 3000?

2001 is the correct answer.


How many 3-digit numbers are found in between 99 and 3000?

There are 900 three-digit numbers, all of which are between 99 and 3,000.


How many four digit no are there between 999 and 3000 through method?

All the numbers between 999 and 3000 are four-digit numbers. You need to subtract 3000 - 999 - 1. The extra -1 is to account for the fact that the numbers 999 and 3000, in this case, are not included.


How many 3 digit numbers between 99 and 3000?

There are 900 three digit numbers between 99 and 3,000 - ranging from 100 to 999


How many three digits numbers are there between 99 and 3000?

There are 900 three digit numbers between 99 and 3,000 - ranging from 100 to 999


How many four digit numbers are found between 500 and 3000?

1000 to 2999 inclusive so 2000 numbers.


How many integers from -3000 to 3000inclusive are divisible by 3?

There are 2001 numbers.


How many palindromes between 1000 and 3000?

A palindrome reads the same forwards as backwards. Therefore the first and last digits must be the same, the second and penultimate the same, and so on. As 1000 & 3000 both have 4 digits, there are two pairs of digits that must be the same: the first and fourth, the second and third. The first digit (and hence last digit) can only be 1 or 2 - a choice of 2 The second digit (and hence third digit) can be any of 0, 1, 2, ..., 9 - a choice of 10 for each of the choices of the first/last digit. Thus there are 2 × 10 = 20 palindromes between 1000 and 3000.