9*9*8*7 = 4536
405
10*9*8=720
Integers of 6 digits are normally greater than integers of 5 digits
Distinct means different from all others. So there can be no repeated digits. Thus, 4124 is not possible because there are two '4' digits. There are 9 ways to choose the first digit (1-9, as 0 is not possible). Subsequently, there are 9 choices for the second digit, since there are 10 possible digits (0-9), but we can't pick the same one as the first digit. Next, there are 8 ways to choose the 3rd digit, since we can't choose the same as either of the first two digits. Finally, there are 7 ways to choose the 4th digit. The answer is 9 * 9 * 8 * 7 = 4536.
4 digits - representing 16 integers.
There are 120 of them.
952 of them.
An infinite amount
405
10*9*8=720
Counting all integers from 1 to 238 inclusive, there are 606 digits between these two numbers.
The sum of all the the integers between 1 and 2008 (2 through 2,007) is 2,017,036.
There are 125 of them.
Two integers.
The sum of all the integers between 1,000 and 2,000 is 1,498,500.
How many
Integers of 6 digits are normally greater than integers of 5 digits