256 (0 through 255)
8
1 byte = 8 bits
8 bits if unsigned, 9 bits if signed
8
An N-bit integer holds 2N different values.For an unsigned integer, the range of values is 0..2N-1 thus.For a signed integer using 2s complement, the range is -2N-1..+2N-1-1.Therefore, the largest positive number that can be stored using 8 bits is 255.
It is not possible. A Byte is 8 bits, the largest possible 8 bit number is '11111111' which is only 255 (in normal decimal numbers).
256 in total - including zero.
0.0000001
Generally, 8 bits at a time. Some instructions deal with 16 bit numbers.
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
Yes, a byte is 8 bits, and a one hexadecimal digit takes up four bits, so two hexadecimal digits can be stored in a byte. The largest hexadecimal digit is F (which is 15 in base ten.) In base two, this converts to 1111, which takes up four bits, which is why it only takes four bits to store a hexadecimal digit. With 8 bits, two hexadecimal digits can be stored (FF would be 11111111, which is 8 bits), and 8 bits make up a byte. Generally, 4 bits are always used to store a hexadecimal digit, using leading zeros where necessary. For example, the hexadecimal digit 5 would be stored as 0101, and the hexadecimal digits 5A would be stored as 01011010.
Generally speaking, eight bits to a byte. There is no actual standard that defines how many bits are in a byte, but it has become something of a de facto standard.
8 bits
8 bits
8 bits is 0.00097656248 KB
byte has 8 bits all bits at 0 = zero all bits at 1 = 255
1 byte = 8 bits (4096 bytes) x (8 bits/byte) = 32768 bits