500 of them.
9*9*8*7 = 4536
1 - even numbers in 1...9999 interval 9999 divided by 2 is 4999 2 - even numbers in 1..999 interval 999 divided by 2 is 499 Doing (1) - (2) = 4999 - 499 = 4500 even numbers in that interval.
One less than 10000.
9000 integers.
There are 2828 integers between 1000 and 9999.
from 1000 to 9999, ie 9999 - 999 = 9000
90 palindromes.
500 of them.
There are 3168 such numbers.
There are 120 of them.
9*9*8*7 = 4536
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
952 of them.
-- The highest 4-digit integer is 9999.-- The lowest one is 1000.-- So what you're really asking is:"How many counting numbers are there past 999 until you get to 9999 ?"Obviously, there are 9,000 of them.
An infinite amount
There are 10 palindromes divisible by 9 between 1000 and 9999.