six 37 39 41 43 45 47
there is 6 and they are 37 39 41 43 45 47
There are 20. {21, 23, 25, 27, 29, 31, 33, 35, 37, 29, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59}
All primes other than two are odd, and two odd numbers add to an even number. So the only possibility is two and 43 minus two. So 2 and 41 is the only pair.
First, the only candidates are odd, so 41, 43, 45, 47, 49 45 is divisible by 5, and 49 by 7, leaving 41, 43, and 47 Now, you can try to divide these number by all of the odd numbers between 3 and themselves (as a simple algorithm), but you will not find that they are divisible by any number other than one and themselves. So, 41, 43, and 47 are prime.
31, 33, 35, 37, 39, 41, 43 & 45 = eight odd numbers !
six 37 39 41 43 45 47
37, 39 and 41
there is 6 and they are 37 39 41 43 45 47
The three odd numbers that add up to 43 are 13, 15, and 15. This is because 13 + 15 + 15 = 43. These numbers are odd because they are not divisible by 2, and their sum equals 43, satisfying the condition of the question.
43 is an odd number and it is also a prime number
31, 37, 41, 43, 47.
31 37 41 43 47
They are: 31 37 41 43 and 47
31 37 41 43 47
odd numbers between 25 and 45 inclusive are 25 27 29 31 33 35 37 39 41 43 45
They are: 31 37 41 43 and 47