20 of them.
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six 37 39 41 43 45 47
there is 6 and they are 37 39 41 43 45 47
All primes other than two are odd, and two odd numbers add to an even number. So the only possibility is two and 43 minus two. So 2 and 41 is the only pair.
First, the only candidates are odd, so 41, 43, 45, 47, 49 45 is divisible by 5, and 49 by 7, leaving 41, 43, and 47 Now, you can try to divide these number by all of the odd numbers between 3 and themselves (as a simple algorithm), but you will not find that they are divisible by any number other than one and themselves. So, 41, 43, and 47 are prime.
22 including both 1 and 43. 22 including both 1 and 43. 22 including both 1 and 43. 22 including both 1 and 43.