0
The factors of 40 are: 1 2 4 5 8 10 20 40 The prime factors are: 2 x 2 x 2 x 5 Answer: 4
Wiki User
∙ 15y ago
Anonymous
8
Add your answer:
Earn +20 pts
How many pairs of prime numbers does 420 have?
420 has four prime factors. Prime factors don't usually travel in pairs.
If pairs of factors separate independently of other pair factors you are dealing with?
If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment
What are the prime factors of 66 in pairs?
Factors go in pairs; prime factors are listed least to greatest. 2, 3 and 11
What are the factors and factor pairs for 27?
Factors: 1, 3, 9, 27. Pairs: (1,27);(3,9).
How are factors different from factor pairs-?
How they're listed. The factors of 20 are 1, 2, 4, 5, 10, 20 The factor pairs of 20 are (20,1)(10,2)(5,4)
What are the pairs of factors for 40?
40,120,210,48,5
What pairs of numbers has a LCM as 40?
40 and any of its factors.
How many pairs of factors does 20 have?
3 pairs
Explain how to find all factors pairs of 40-?
Explaining how to find all factors pairs of 40 is easy. All you have to do is find which whole numbers 40 can be divided into.
How many factors does 40 have?
40,=1,2,4,5,8,10,20 AND 40
How many pairs of factors does 4 have?
Factors for 4 are: 1, 2, 4 It has 2 pairs = 1 * 4 or 2 * 2
How many pairs of prime numbers does 420 have?
420 has four prime factors. Prime factors don't usually travel in pairs.
What are the pairs of factors for 80?
(1, 80); (2, 40); (4, 20); (5, 16); (8, 10).
If a squirrel normally has 40 pairs of chromosomes in its cells after mitosis occurs how many pairs of chromosomes would be in each of the squirrels body cells?
40
How many pairs of prime numbers have a sum of 40?
There 4 pairs of primes that can give a sum 40 in addition. They are (3,37), (11,29), (17,23),(19,21).
How many chromosomes does a duck have?
None.
If pairs of factors separate independently of other pair factors you are dealing with?
If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment
