2 times
30+31+32+33
41+42+43
The integers are 5 and 7.
No, a negative times a negative would be a positive and a positive times a positive would also be positive, and anything multiplied by zero would still be zero
9,11,13
I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.
The product of two negative integers is positive as for example -4 times -5 = 20
The 3 consecutive odd positive integers are 7, 9 and 11.
The integers are 5 and 7.
They are 6 times 8 = 48
No, a negative times a negative would be a positive and a positive times a positive would also be positive, and anything multiplied by zero would still be zero
One possible answer is -4 and -3.
10-11-12
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The sum of three consecutive integers is -72
9,11,13
When you multiply two integers of the same sign, the answer is always positive. A positive times a positive is positive and a negative times a negative is positive.
There are no such integers.
negative times negative = positive positive times positive = positive negative times positive = negative positive times negative = negative