189 = 2 x 2 x 3 x 3 x 3 = 22 x 33
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
24 as a product of its prime factors in index form: 2| 24 === 2| 12 === 2| 6 === .....3 Prime factorization of 24= 2 x 2 x 2 x 3
Well, isn't that just a happy little question! To write 160 as a product of its prime factors, we can express it as 2^5 * 5. In index form, this would be written as 2^5 * 5^1. Just remember, there are no mistakes, only happy little accidents in math!
Prime factors are numbers that are: prime, and multiply to make the number you want, in this case 75. 75 as a product of prime factors would be, 3 x 5 x 5; if you work this out, the result is 75.
The product of all the common prime factors is the GCF. The product of all common factors would vary according to the list.
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
24 as a product of its prime factors in index form: 2| 24 === 2| 12 === 2| 6 === .....3 Prime factorization of 24= 2 x 2 x 2 x 3
140 = 2 x 2 x 5 x 7 = 22 x 5 x 7
Well, isn't that just a happy little question! To write 160 as a product of its prime factors, we can express it as 2^5 * 5. In index form, this would be written as 2^5 * 5^1. Just remember, there are no mistakes, only happy little accidents in math!
Prime factors are numbers that are: prime, and multiply to make the number you want, in this case 75. 75 as a product of prime factors would be, 3 x 5 x 5; if you work this out, the result is 75.
The product of all the common prime factors is the GCF. The product of all common factors would vary according to the list.
To work out the prime factors of 180 in index form, you first need to find the prime factors of 180. Start by dividing 180 by the smallest prime number, which is 2. Continue dividing by prime numbers until you cannot divide any further. The prime factors of 180 are 2, 2, 3, 3, and 5. In index form, this would be written as 2^2 * 3^2 * 5.
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
3 x 3 x 3 x 7 Or, if you want it in the index form, it would be 3 cubed (little three above the '3') x 7.
To find the prime factors of 84, we first break it down into its prime factors: 84 = 2^2 * 3 * 7. Then, to calculate 84 cubed, we cube each prime factor: (2^2)^3 * 3^3 * 7^3 = 2^6 * 3^3 * 7^3. So, 84 cubed can be expressed as the product of its prime factors in index form as 2^6 * 3^3 * 7^3.
That's asking for the prime factorization. Writing 60 as a product of its prime factors would be 2 x 2 x 3 x 5 = 60.
Oh honey, let me break it down for you. 160 can be expressed as 2^5 * 5^1. In index form, that would be written as 2^5 * 5. So there you have it, 160 expressed as a product of prime numbers in index form. Hope that clears things up for ya!