140 = 2 x 2 x 5 x 7 = 22 x 5 x 7
the prime factorization of 150= 2x3x52 If we use all the factors, the answer would of course be 150 if we use just 2,3 and a single 5, not 52 , then the answer is 30
Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).
The set of prime factors of the numbers from 1 to 15,000 would be the set of prime numbers between 1 and 15,000. The link below has a list of the first 10,000 prime numbers, so if you take the primes less than 15,000, you will have the set of prime factors of the first 15,000 numbers. For prime factors of individual numbers, check the related question, "What are the prime factors of the numbers from 1 to 200?" Also check for WikiAnswers questions in the form of "What are the prime factors of __?" and "What are the factors and prime factors of __?"
Well, let's take a moment to appreciate the number 240. If we break it down into its prime factors, we get 2 x 2 x 2 x 2 x 3 x 5. In index form, this would be written as 2^4 x 3 x 5. Isn't it wonderful how numbers can be broken down into their simplest, most beautiful form?
To find what equals 102 in multiplication, you would need to factorize 102 into its prime factors. 102 = 2 x 3 x 17. Therefore, any combination of these prime factors multiplied together will equal 102. For example, 6 x 17 = 102.
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
24 as a product of its prime factors in index form: 2| 24 === 2| 12 === 2| 6 === .....3 Prime factorization of 24= 2 x 2 x 2 x 3
189 = 2 x 2 x 3 x 3 x 3 = 22 x 33
Well, isn't that just a happy little question! To write 160 as a product of its prime factors, we can express it as 2^5 * 5. In index form, this would be written as 2^5 * 5^1. Just remember, there are no mistakes, only happy little accidents in math!
Prime factors are numbers that are: prime, and multiply to make the number you want, in this case 75. 75 as a product of prime factors would be, 3 x 5 x 5; if you work this out, the result is 75.
The product of all the common prime factors is the GCF. The product of all common factors would vary according to the list.
To work out the prime factors of 180 in index form, you first need to find the prime factors of 180. Start by dividing 180 by the smallest prime number, which is 2. Continue dividing by prime numbers until you cannot divide any further. The prime factors of 180 are 2, 2, 3, 3, and 5. In index form, this would be written as 2^2 * 3^2 * 5.
The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210
3 x 3 x 3 x 7 Or, if you want it in the index form, it would be 3 cubed (little three above the '3') x 7.
To find the prime factors of 84, we first break it down into its prime factors: 84 = 2^2 * 3 * 7. Then, to calculate 84 cubed, we cube each prime factor: (2^2)^3 * 3^3 * 7^3 = 2^6 * 3^3 * 7^3. So, 84 cubed can be expressed as the product of its prime factors in index form as 2^6 * 3^3 * 7^3.
That's asking for the prime factorization. Writing 60 as a product of its prime factors would be 2 x 2 x 3 x 5 = 60.
Oh honey, let me break it down for you. 160 can be expressed as 2^5 * 5^1. In index form, that would be written as 2^5 * 5. So there you have it, 160 expressed as a product of prime numbers in index form. Hope that clears things up for ya!