Yes. Since 7 is a Prime number, you have found all the prime numbers, with 7 being the final prime factor.
All numbers ending in 0 and 5 are divisible by 5 and since 28655 ends in 5, it is divisible by 5 and therefore not prime.
(98) = 2 * (49) = 7 * 7 ( both primes, end sequence) so > prime factors are : 21 * 72
5 itself is a prime number, so if you count 5 as ending in 5 that is one prime number. Other than that any number ending in 5 would be some multiple of 5 and therefore could not be a prime number.
Dim prime, nprime = TRUEn=cint(inputbox("Enter a number to find whether it is Prime or Not"))for i=2 to (n-1)If n mod i = 0 thenprime = FalseExit forEnd ifNextIf prime thenmsgbox "Yes! It is a Prime number"Elsemsgbox "No! it is not a prime number"End if
Oh, dude, expressing 294 as the product of prime factors is like breaking down a complicated relationship. You start by dividing 294 by the smallest prime number, which is 2. Then you keep going until you can't divide anymore. In the end, you'll have 2 x 3 x 7 x 7, which is the prime factorization of 294. Easy peasy lemon squeezy!
567
2 x 5 x 5 = 50 satisfies those conditions.
It's unclear why anyone would find that necessary. Even numbers end in 0, 2, 4, 6, 8. Odd numbers end in 1, 3, 5, 7, 9. It's more efficient to just look at the numbers.
Not really. A factor string is a multiplication sentence. A factor tree is a way of notating the process of finding the prime factorization of a given number. End result: 4 x 9 can be a factor string for 36, but can't be a prime factorization. The prime factorization of 36 is 2 x 2 x 3 x 3.
You have to find the smallest prime number that can go into 76, which is 2 and find out what 76/2 is. The, you would have to take the non-prime number and find the smallest prime number that can go into that, and divide by those to numbers again. The prime number you had with 76, you would keep that and keep dividing the non-prime numbers until you end up with all prime numbers.
2 x 5 x 5 = 50 2 x 2 x 5 = 20
There are a lot of possibilities. The seventh square number is 49. 5 times 5 times any other prime number will be greater than 49. 5 times any pair of prime numbers seven or greater will also satisfy the conditions.
no, because it has a 2 at the end. if the last digit in the number is an even number, then it is not a prime number. Also if the only factors of the number is 1 and itself then it is a prime number. example 1: 5,622 = not prime number.... example 2: 13=prime number because the only factors are 1 and 13.
The process is roughly the same; you're going to break a number down into component parts, but the end results are different. The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36 The prime factorization of 36 is 2 x 2 x 3 x 3
Factor out prime by prime or factor out the term by the number you know (e.g. factor out 10 since 1330 has a zero at the end.) You should get: 1330 = 10 x 133 = 2 x 5 x 7 x 19 [So this is the prime factorization of 1330] Check: 2 x 5 x 7 x 19 = 1330
All numbers ending in 0 and 5 are divisible by 5 and since 28655 ends in 5, it is divisible by 5 and therefore not prime.
Other than 2, no prime numbers are even. So prime numbers can't end in even numbers. After 5, no prime number can end in 5. After 5, all prime numbers end in 1, 3, 7 or 9.