Yes. If a x b = 0 then either a = 0, b = 0, or a = b = 0.
The product of two rational numbers, X and Y, is smaller than either of them if both are between 0 and 1.
A prime number is one that has only 2 factors, itself and one. A composite number is one that can be written as the product of two numbers that are not itself. By these definitions, 1 and 0 fail to be either composite or prime. 1 can only be divided by one, so it does not have the 2 necessary factors to be prime or the multiple required to be composite. 0 on the other hand can be divided evenly by every number, but no two numbers that are not 0 can be multiplied to get a product of 0.
I'll take this question to mean: "What is the smallest possible product of two different prime numbers?" # 0 # 3 # 5 # 6 You've provided two requirements: # The number must have two factors. # Both factors must be prime. Let's break down the following into possible factors: 0 = 0 3 = 3 * 1 5 = 5 * 1 6 = 1 * 6, 2 * 3 Since neither 0 nor 1 are prime numbers, we're left with only one option. 2 * 3 = 6
Two numbers with a difference of 5 have a product of 6800. x and (x + 5) are our numbers. Let's multiply them together. (x) (x+5) = x2 + 5x That is equal to the 6800 specified. x2 + 5x = 6800 >> x2 + 5x - 6800 = 0 (x + 85) (x - 80) = 0 x + 85 = 0, so x = -85 (this in not a correct answer - it has the wrong sign) x - 80 = 0, so x = 80 (a correct answer, and one of the two numbers we need) Since x = 80, x + 5 = 85 Our numbers are 80 and 85. Let's check. 80 times 85 = 6800. Our work checks.
0 Look at the product of the first 3 prime numbers: 2 x 3 x 5 = 30. Any number multiplied by 30 will have a 0 in the units digit. So, no matter how many prime numbers you are multiplying, if once you have a number ending in 0, all of the rest will end in 0.
The product of two even numbers is even. The product of two even numbers will be even. If they are both positive numbers, it will be greater than both of them. If one of them ends in 0, the product will end in 0.
zero
9+0=9?
No. If one of the numbers is 0 it is less; if one of the numbers is 1 it is the same as one of them; otherwise the product is greater than either
As a general principle, you can find the LCM of two numbers by dividing their product by their GCF. This one won't work. The product of any two numbers with 5 as a common factor would have to end in 5 or 0.
If one is zero, then the product is always zero.(Think about it ... you take 279 zero times. How much do you have ?)
You can compare them by looking at them (they are the same)subtracting one from the other (answer = 0)dividing one by the other (the quotient is 1).
None. If the two numbers have a quotient of 9 then one of them must be 9 times as large as the other. In that case, their difference cannot be 0.
The product of the ten one-digit numbers is 0.
If the numerator is 0 then, provided the denominator is not 0, the answer is always 0.
137 and 0
-5 and +5.