Best Answer

15/36

Explanation:

dice 1 can roll 6 possible numbers

dice 2 can roll 6 possible numbers

possible outcomes: 6x6= 36

prime outcomes = 2, 3, 5, 7, 11

2-->(1,1)-->1

3-->(1,2) and (2,1)-->2

5-->(1,4) (4,1) (2,3) and (3,2) -->4

7-->(1,6) (6,1) (2,5) (5,2) (3,4) and (4,3)-->6

11->(5,6) (6,5)-->2

1+2+4+6+2=15

15/36

Q: If you roll two standard dice what is the probability that the sum will be a prime number?

Write your answer...

Submit

Still have questions?

Continue Learning about Basic Math

The probability of getting at least one prime number in two dice is 3/4.

1 out of 2.

The prime numbers from 1-6 are 2, 3, 5 (1 is not prime). There are 3 prime numbers on a dice and 6 total. therefore the probability of rolling a prime is 3/6. The probability of getting a tails when flipping a coin is 1/2. Therefore you just multiply the two. 3/6 * 1/2 = 1/4

On a standard die, 2:1 in favour. This would be correct if 1 and 2 are accepted as prime numbers, which is allowed by some mathematicians and theories though not by all. ---- Having worked it out myself, I believe there is actually an even probability: Prime numbers: * 2 * 3 * 5 Not-prime numbers: * 1 * 4 * 6

Since there are 3 prime numbers, 13, 17, and 19, in the range 12 to 19, the probability of throwing a prime number on a fair eight sided die numbered 12 to 19 is 3 in 8.

Related questions

13/36

The probability is 0 since if both dice show the number 6, their sum is 12 which is not a prime.

The probability of getting at least one prime number in two dice is 3/4.

1 out of 2.

The probability of rolling two prime numbers on a standard pair of dice is 1 in 4, or 0.25. Take the probability of rolling a prime on one die, 3 in 6, or 1 in 2, or 0.5, and square it.

The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.

false.

If the numbers are 1 to 6, there are three prime numbers in that range, a probability of 50%.

50% 1/2 0.5

There are 36 permutations of two standard 6 sided dice. Of those, 15 are prime, namely 2, 3, 3, 5, 5, 5, 5, 7, 7, 7, 7, 7, 7, 11, and 11. The probability of rolling a prime number, then, is 15 in 36, or 5 in 12, or about 0.4167. It does not matter how many times you roll the dice.

The probability is 1 out of two. The primes you can roll are 2,3, and 5.

Assuming you mean the sum of the two dice is a prime number, then: The possible outcomes are 2, 3, 5, 7, 11 which occur 1, 2, 4, 7, 2 times respectively. There are 36 possible outcomes → pr(prime_sum) = (1+2+4+7+2)/36 = 16/36 = 4/9 If you mean that both dice must show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a prime number is 3/6 = ½ → probability both show a prime number is ½ × ½ = ¼ If you mean either or both dice could show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a primes is 3/6 = ½ → probability of a die not showing a prime is 1 - ½ = ½ → probability of neither die showing a prime is ½ × ½ = ¼ → probability of either or both dice show a prime is 1 - ¼ = ¾