f(x) = x2-4x-5 = x2-5x+x-5 = x(x-5)+1(x-5) = (x+1)(x-5) Factors of f(x) are (x+1) and (x-5).
If the missing signs are pluses, that factors to (x + 5)(x + 5) or (x + 5)2
Original problem: x^2-x-20x2-25/x2-16x^2-x-30 Revised: [(x2 - x - 20)(x2 - 25)] / [(x2 - 16)(x2 - x - 30)] Solution: Factor the polynomials: {[(x - 5)(x + 4)][(x + 5)(x - 5)]} / {[(x +4)(x - 4)][(x - 6)(x + 5)]} Cancel common factors: [(x - 5)(x - 5)] / [(x - 4)(x - 6)] ---> Simplest form (or final answer) (Optional) Expand: (x2 - 10x + 25) / (x2 - 10x + 24)
400 = 2 x 2 x 2 x2 x 5 x 5 (or 24 x 52)
1, +x, -x, and x2 , as well as any factors of 'x' .
The factors of x2 - x - 20 are (x - 5) and (x + 4) because when you multiply them together, they come out to x2 - x - 20.
If the expression is, x2 + 2x - 15 this has factors of (x + 5)(x - 3). If the expression is, x2 - 2x - 15 then the factors are (x - 5)(x + 3)
(X + 5)(X + 1) FOIL this. X2 + 1X + 5X + 5 Gather terms. X2 + 6X + 5 ----------------------------those were the factors
(x - 5)(x - 5) or (x - 5)2
This can be factored in multiple ways, depending on the signs. X2+10x+25 factors into (x+5)2 or (x+5)(x+5). X2-10x+25 factors into (x-5)2 or (x-5)(x-5). If 25 is being subtracted, then the trinomial is impossible to factor.
f(x) = x2-4x-5 = x2-5x+x-5 = x(x-5)+1(x-5) = (x+1)(x-5) Factors of f(x) are (x+1) and (x-5).
x2-5x-50 = (x+5)(x-10) when factored
x2 - x + 30 does not have any factors. If on the other hand you wanted to factor out: x2 - x - 30 Then it can be done as follows: = x2 - 6x + 5x - 30 = x(x - 6) + 5(x - 6) = (x + 5)(x - 6)
(x - 3)(x - 5)
The factors of x2 are x and x x times x plus 1 = x2 + x
If that's x2, the answer is (x - 5)(x - 4)
X2 - 4X - 5 as an expression, or equation is factorable when the question, what two factors of - 5 add to - 4 is answered ( X + 1)(X - 5) X = - 1 ------------and X = 5 ---------------