The factors of x2 are x and x.
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f(x) = x2-4x-5 = x2-5x+x-5 = x(x-5)+1(x-5) = (x+1)(x-5) Factors of f(x) are (x+1) and (x-5).
If the missing signs are pluses, that factors to (x + 5)(x + 5) or (x + 5)2
Original problem: x^2-x-20x2-25/x2-16x^2-x-30 Revised: [(x2 - x - 20)(x2 - 25)] / [(x2 - 16)(x2 - x - 30)] Solution: Factor the polynomials: {[(x - 5)(x + 4)][(x + 5)(x - 5)]} / {[(x +4)(x - 4)][(x - 6)(x + 5)]} Cancel common factors: [(x - 5)(x - 5)] / [(x - 4)(x - 6)] ---> Simplest form (or final answer) (Optional) Expand: (x2 - 10x + 25) / (x2 - 10x + 24)
400 = 2 x 2 x 2 x2 x 5 x 5 (or 24 x 52)
1, +x, -x, and x2 , as well as any factors of 'x' .