(x - 3)(x - 5)
It equals 285
15 + 5x '5' is a factor of both '15' & '5' . So take '5' out!!! Hence 5(3 + x)
15 x 6 or the long way is 90
n plus 15.n plus 15.n plus 15.n plus 15.
Whatever isn't 5(x - 1)(2x + 3)
15 + 5x '5' is a factor of both '15' & '5' . So take '5' out!!! Hence 5(3 + x)
5(x + 3)(x + 1)
It equals 285
(x + 15)(x - 4)
First add 15 and 45. Then find the factors. 15+45=60 The factors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, and 30.
15 x 6 or the long way is 90
using the quadratic formula -4/3 and -0.4
n plus 15.n plus 15.n plus 15.n plus 15.
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
Whatever isn't 5(x - 1)(2x + 3)
12 + 15 + 63 + 12 + 24 + 34 + 23 + 15 = 198
16 + 15 = 31