Not necessarily. Consider 444.
The digits are not different.
The first and second digits are not multiples of 3
The first digit is not greater than the second digit.
In spite of all that, 444 is a 3-digit number
117. All multiples of 9 have digits that add up to something divisible by 9. Examples, 117, 36, 45, 54 all have digits that add up to 9.
Integers of 6 digits are normally greater than integers of 5 digits
4 x 578 = 2312 8 x 754 = 6032
Any 5-digit number is greater than a 4-digit one.
Prime number between 196 and 289 whose digits add to 14? Possibles 239, 248, 257, 266, 275, 284. 248, 266 and 284 are multiples of 2, 275 is a multiple of 5. This leaves 239 and 257. Only 239 has one digit which is the square of another. So there you have it.
0.12 Or 102 if you do not want to include non integers.
It's the number that has more digits to the left of the decimal point (if there is no decimal point, it's the number with more digits). If the number of digits to the left of the decimal point is the same, find the position farthest to the left where the digits are different. The number with the greater of those two digits is the greater number. For example, 10000 is greater than 9999 because 10000 has more digits, and 6350 is greater than 6349 because the farthest-left position that is different is the tens place, and 5 is greater than 4.
What is the units digit of the least whole number greater than 1000 whose digits are all different?
It is greater because with more digits the greater the value of the number will be.
All multiples of 3 have digits that add up to a multiple of 3.
The units digits start with 8 and go down in steps of 2. The units digit repeats every 5 multiples, The last pair of digits repeat every 25 multiples.
117. All multiples of 9 have digits that add up to something divisible by 9. Examples, 117, 36, 45, 54 all have digits that add up to 9.
The number has to be 450. The number is 3 digits, and it's divisible by 8.
ALL such numbers will be multiples of 9.
4500
one
88 of them.