No. A complex number consists of a real part and a imaginary part. If the real part equals zero, there is only the imaginary left and you could therefor argue that it is an imaginary number (or else it would still be a complex number -with a real part=0)
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No. All Complex Numbers are of the form a + bi where a and b are Real Numbers and i is the square root of -1. So only ones where a = 0 are pure Imaginary Numbers.
A complex number z has two parts - a real part and an imaginary part - and is of the form:z := x + iywherex and y are real numbersi represents √-1, that is i2 = -1.("x" is the real part, "iy" is the imaginary part)As x and y are real numbers, they can be any real number including 0.If x = 0, the resulting complex number z is of the form "iy" and is totally imaginary;if y = 0, the resulting complex number z is of the form "x" and is totally real.Thus real numbers are a subset of complex numbers, that is every real number is a complex number, but not every complex number is a real number.yes
Yes. The letter i denotes the value of the "positive square root" of -1. So i² = -1. But also (-i)² = -1 as well. Remember that for every number there is a "positive" and "negative" square root. So if you want the square root of -4, you can do this: -4 = (-1)(4). So sqrt(-4) = sqrt[(-1)(4)] = sqrt(-1)*sqrt(4) = i*2 or -i*2. We usually write these as 2i and -2i.
"a + bi" is a common way to write a complex number. Here, "a" and "b" are real numbers.Another common way to write a complex number is in polar coordinates - basically specifying the distance from zero, and an angle.
because somtimes there isn't an answer to every equation like what's the square root of -16.... there is no answer so we would just use an imaginary number which is i.It turns out that these are important in a practical sense. Imaginary numbers turn up all the time in quantum mechanics and certain types of electronic circuits as well.