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Yes.

Since they are rational numbers, let's call the first one a/b and the second one c/d where a,b,c, and d are integers.

Now we can subtract by finding a common denominator. Let's use bd.

So we have ad/bd-cb/bc= (ad-bc)/CD which is rational since we know ad and bc are integers being the product of integers and CD is also an integers.

Call ad-bd=P and call CD=Q where P and Q are integers. We now see the difference is of two rationals is rational.

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Q: Is the difference of two rational numbers always a rational number?
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Related questions

The difference of two rational numbers is always a rational number?

Yes, that's true.


Is it true that The difference of two rational numbers always a rational number?

Yes. The rational numbers are a closed set with respect to subtraction.


Is The difference of two real numbers always an irrational number?

No. 5 and 2 are real numbers. Their difference, 3, is a rational number.


Why is the difference of two rational numbers always a whole number?

The question cannot be answered because it is nonsensical. The difference between two rational numbers is very very rarely a whole number.


Is the difference of two rational numbers always rational?

Yes. This is the same as asking for one rational number to be subtracted from another; to do this each rational number is made into an equivalent rational number so that the two rational numbers have the same denominator, and then the numerators are subtracted which gives a rational number which may possibly be simplified.


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The product of two rational numbers is always a rational number.


What s happens when rational numbers are multplied?

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Would the difference of a rational number and a rational number be rational?

The difference of two rational numbers is rational. Let the two rational numbers be a/b and c/d, where a, b, c, and d are integers. Any rational number can be represented this way. Their difference is a/b-c/d = ad/bd-cb/bd = (ad-cb)/bd. Products and differences of integers are always integers. This means that ad-cb is an integer, and so is bd. Thus, (ad-cb)/bd is a rational number (since it is the ratio of two integers). This is equivalent to the difference of the original two rational numbers.


Does there exist an irrational number such that its square root is rational?

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Is the difference of rational numbers a rational number?

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What would be difference of 2 rational numbers?

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