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It can be but it certainly doesn't have to be.

3/4 and 1/2 are both rational numbers.

(3/4) - (1/2) = 1/4, which is not an integer.

Q: Is the difference of two rational numbers an integer?

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Rational numbers are represented in the form of p/q , where p is an integer and q is not equal to 0.Every natural number, whole number and integer can be represented as rational number.For example take the case of integer -3, it can be represented in the form of p/q as -3/1 and q is not equal to zero, which means that rational numbers consist of counting numbers, whole numbers and integers.Now, what will be the result of product of any two rational numbers?Let us take the case of two rational numbers which are x/y & w/z, their product is equal toxw/yz, which is a rational number because multiplication of x and w results in an integer and also multiplication of y and z results in an integer which satisfies the property of rational numbers, which is in the form of p/q.So, product of any two rational numbers is a rational number.

A perfect square is a square of an integer.The set of integers is closed under multiplication. That means that the product of any two integer is an integer. Therefore the square of an integer is an integer.Integers are rational numbers so the square [which is an integer] is a rational number.

Any fraction that does not equal to a whole number is real and rational, but not an integer. 1/5 is rational because it is represented by the division of two integers, but it is not itself an integer, which are natural numbers such as 1, 2, and 3.

Yes, that's true.

Find the arithmetic average of the two rational numbers. It will be a rational number and will be between the two numbers.

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No, it is not generally true.

When you consider how many rational numbers there are, the difference between any two of them is hardly ever an integer. Examples: 5 - 4/5 = 41/5 5/6 - 2/3 = 1/6 3.274 - 1.368 = 1.906 All of the nine numbers in these examples are rational numbers.

The difference of two rational numbers is rational. Let the two rational numbers be a/b and c/d, where a, b, c, and d are integers. Any rational number can be represented this way. Their difference is a/b-c/d = ad/bd-cb/bd = (ad-cb)/bd. Products and differences of integers are always integers. This means that ad-cb is an integer, and so is bd. Thus, (ad-cb)/bd is a rational number (since it is the ratio of two integers). This is equivalent to the difference of the original two rational numbers.

no

Yes.

Two is an integer. All integers are rational numbers.

Rational numbers are represented in the form of p/q , where p is an integer and q is not equal to 0.Every natural number, whole number and integer can be represented as rational number.For example take the case of integer -3, it can be represented in the form of p/q as -3/1 and q is not equal to zero, which means that rational numbers consist of counting numbers, whole numbers and integers.Now, what will be the result of product of any two rational numbers?Let us take the case of two rational numbers which are x/y & w/z, their product is equal toxw/yz, which is a rational number because multiplication of x and w results in an integer and also multiplication of y and z results in an integer which satisfies the property of rational numbers, which is in the form of p/q.So, product of any two rational numbers is a rational number.

1 is rational. Rational numbers are numbers that can be written as a fraction. Irrational Numbers cannot be expressed as a fraction.

Yes.

Yes, it is.

Wrong because 3/4 and a 1/4 are rational numbers that add up to 1

No. You cannot get an integer between 1.2 and 1.3