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All integers greater than 1 are one or the other.

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No, it's composite.

Q: Is the number 141 neither prime nor composite?

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141 is a composite because 1, 3, and 47 goes in it

141 is a composite numbers. Its factors are 1, 3, 47, and 141.

The number 41 is a prime number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite.To test a number to find out if it is prime or composite, try dividing it by the first few prime numbers:41 ÷ 2 = 20 r 141 ÷ 3 = 13 r 241 ÷ 5 = 8 r 141 ÷ 7 = 5 r 6We don't have to test 4 or 6, since they are both divisible by 2. The divisor (7) is now larger than the result (5 remainder 6), so we can stop. 41 is prime.

47*3 = 141 therefore not a prime number

151 is the 36th prime number.

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141 has two prime factors, one composite factor and one that is neither.

141 is a composite because 1, 3, and 47 goes in it

141 is a composite number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 have a different name.

It is a composite number, not a prime number. 2 and 141 are two of its factors.

141 is a composite numbers. Its factors are 1, 3, 47, and 141.

The number 41 is a prime number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite.To test a number to find out if it is prime or composite, try dividing it by the first few prime numbers:41 ÷ 2 = 20 r 141 ÷ 3 = 13 r 241 ÷ 5 = 8 r 141 ÷ 7 = 5 r 6We don't have to test 4 or 6, since they are both divisible by 2. The divisor (7) is now larger than the result (5 remainder 6), so we can stop. 41 is prime.

47*3 = 141 therefore not a prime number

141

No, 141=3*47.

151 is the 36th prime number.

I am not sure what you are asking but 141 is divisible by the number 1, itself (141) and certainly by the number 3 so it is not a prime number.

yes. it is