141 is a composite number. A Prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 have a different name.
141 is a composite because 1, 3, and 47 goes in it
141 is a composite numbers. Its factors are 1, 3, 47, and 141.
141 has two prime factors, one composite factor and one that is neither.
It is a composite number, not a prime number. 2 and 141 are two of its factors.
All integers greater than 1 are one or the other.
yes. it is
The prime factorization of 141 is 47*2.
neither prime or composite
It is prime
It would be impossible to list them all, since numbers go on forever, but here are some of them: 2 - Prime 3 - Prime 4 - Composite 5 - Prime 6 - Composite 7 - Prime 8 - Composite 9 - Composite 10 - Composite 11 - Prime 12 - Composite 13 - Prime 14 - Composite 15 - Composite 16 - Composite 17 - Prime 18 - Composite 19 - Prime 20 - Composite 21 - Composite 22 - Composite 23 - Prime 24 - Composite 25 - Composite 26 - Composite 27 - Composite 28 - Composite 29 - Prime 30 - Composite 31 - Prime 32 - Composite 33 - Composite 34 - Composite 35 - Composite 36 - Composite 37 - Prime 38 - Composite 39 - Composite 40 - Composite 41 - Prime 42 - Composite 43 - Prime 44 - Composite 45 - Composite 46 - Composite 47 - Prime 48 - Composite 49 - Composite 50 - Composite
47*3 = 141 therefore not a prime number
The number 41 is a prime number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite.To test a number to find out if it is prime or composite, try dividing it by the first few prime numbers:41 ÷ 2 = 20 r 141 ÷ 3 = 13 r 241 ÷ 5 = 8 r 141 ÷ 7 = 5 r 6We don't have to test 4 or 6, since they are both divisible by 2. The divisor (7) is now larger than the result (5 remainder 6), so we can stop. 41 is prime.