Yes, it is an irrational number. It is because sqrt. root of 3 can't be expressed in the form p/q [where q isn't equal to 0].
If the square root of a natural number is not an integer, then it is irrational. Another way to look at it: if a natural number N falls between two perfect squares, then the square root of N is irrational.So in this case, 12 is between 9 (3 squared) and 16 (4 squared). So the square root of 12 is between 3 and 4, and also the square root of 12 is irrational.
No. Square root of 9=3. 3=3/1. Therefore not all square roots are irrational
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.
Pi, the numerical value of the ratio of the circumference of a circle to its diameter.
No. The cube root of 3, for example is irrational. But the square of cubert(3) is 3 to the power 2/3, which is irrational. Another example, pi2 is irrational (in fact so is pi to any non-zero power).
The square root of 3 is an irrational number
The square root of -3 is an imaginary number and the square root of 3 is an irrational number that can't be expressed as a fraction
YES.... squre root of 3 is in irrational number..
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
Because 3 is a prime number and as such its square root is irrational
No, because the square root of 3 is an irrational number
It is rational.The square root of 9 is 3 and it is a rational number
The square root of 3 is an irrational number
It is an irrational number and it is about 8.660254038
No, 3 is a rational number. Pi and the square root of 2 are irrational numbers.
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
no. an example of an irrational number would be like the square root of 3