Yes, it is an irrational number. It is because sqrt. root of 3 can't be expressed in the form p/q [where q isn't equal to 0].
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If the square root of a natural number is not an integer, then it is irrational. Another way to look at it: if a natural number N falls between two perfect squares, then the square root of N is irrational.So in this case, 12 is between 9 (3 squared) and 16 (4 squared). So the square root of 12 is between 3 and 4, and also the square root of 12 is irrational.
IRRATIONAL sqrt(15) = sqrt(3 x 5) =sqrt(3) X sqrt(5) Since the 'square roots' of prime numbers , '3' & '5' in this case, are irrational , then the square root od '15' is irrational .
No. Square root of 9=3. 3=3/1. Therefore not all square roots are irrational
The decimal number 1.73205081 can be expressed as an irrational number, specifically the square root of 3. In fraction form, this would be written as √3. Since the square root of 3 cannot be simplified further into a rational fraction, it remains as √3 in its simplest form.
no.No. The square root of 5 is an irrational number. The two closest numbers with integer square roots are 4 (with a square root of 2) and 9 (with a square root of 3). Since there are no integers between 2 and 3 and 5 lies between 4 and 9, it's pretty evident that it can't have an integer square root.