No. Integers are counting numbers, or whole numbers.
Only squares of integers (e.g. 4, 9, 16, 25) can have integer roots.
Square roots of numbers that are not squares of integers are also not rational numbers, because they have repeating or non-repeating decimal extensions.
The square root of an integer is a CYCLOTOMIC integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
Square root of 25 = 251/2 = 5, which is an integer. So the square root of 25 is integer.
No, it is not.The square root of any positive integer is eitheran integer orirrational
None. 1000 does not have an integer square root. 312 = 961 and 322 = 1024 and there is no integer between 31 and 32 so there can be no integer whose square is 1000.
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
No
No, they are not.
7
Yes, it is 7.
Because no two integer numbers divide to make the number "square root of 7".
The square root of an integer is a CYCLOTOMIC integer.
Negative 64 is the square root of an integer. The square root of -64 is not an integer.
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
The square root of 3 is not an integer.
Is the square root of a 100 is a integer
7 is not the square of a perfect integer - the square root of 7, rounded to two decimal places, is 2.65.