Yes Yes, the sum of two irrational numbers can be rational. A simple example is adding sqrt{2} and -sqrt{2}, both of which are irrational and sum to give the rational number 0. In fact, any rational number can be written as the sum of two irrational numbers in an infinite number of ways. Another example would be the sum of the following irrational quantities [2 + sqrt(2)] and [2 - sqrt(2)]. Both quantities are positive and irrational and yield a rational sum. (Four in this case.) The statement that there are an infinite number of ways of writing any rational number as the sum of two irrational numbers is true. The reason is as follows: If two numbers sum to a rational number then either both numbers are rational or both numbers are irrational. (The proof of this by contradiction is trivial.) Thus, given a rational number, r, then for ANY irrational number, i, the irrational pair (i, r-i) sum to r. So, the statement can actually be strengthened to say that there are an infinite number of ways of writing a rational number as the sum of two irrational numbers.
No - the sum of any two rational numbers is still rational:
Not necessarily. 3+sqrt(2) and 3-sqrt(2) are both irrational numbers. Their sum is 6 - a rational.
Yes.An example:1 + 2^(0.5) is an irrational number,1 -(2^(0.5)) is also a irrational number.(1 + 2^(0.5)) + (1- 2^(0.5)) = 22 is a rational number.Therefore the sum of two irrational numbers can equal a rational number.But this is not the question. Can you add two irrational numbers to get another irrational number. Yes. Almost all additions of two irrational numbers result in another irrational number. For instance pi (3.141...) and e (2.718...) are both irrational, and so is their sum. In some sense you have to work quite hard to make the sum not irrational (i.e. rational) because the two decimal expansions have to conspire together either to cancel out or to give a repeating decimal.Actually, pi+e may or may not be irrational. This hasn't been proved either way. See: http://en.wikipedia.org/wiki/Irrational_number (under "Open Questions")Yes. For example, pi + (-pi) = 0.any number that is a non-terminating decimal is called an irrational number.
not always. nothing can be generalized about the sum of two irrational number. counter example. x=(sqrt(2) + 1), y=(1 - sqrt20) then x + y = 1, rational.
irrational
The sum or the difference between two irrational numbers could either be rational or irrational, however, it should be a real number.
Yes Yes, the sum of two irrational numbers can be rational. A simple example is adding sqrt{2} and -sqrt{2}, both of which are irrational and sum to give the rational number 0. In fact, any rational number can be written as the sum of two irrational numbers in an infinite number of ways. Another example would be the sum of the following irrational quantities [2 + sqrt(2)] and [2 - sqrt(2)]. Both quantities are positive and irrational and yield a rational sum. (Four in this case.) The statement that there are an infinite number of ways of writing any rational number as the sum of two irrational numbers is true. The reason is as follows: If two numbers sum to a rational number then either both numbers are rational or both numbers are irrational. (The proof of this by contradiction is trivial.) Thus, given a rational number, r, then for ANY irrational number, i, the irrational pair (i, r-i) sum to r. So, the statement can actually be strengthened to say that there are an infinite number of ways of writing a rational number as the sum of two irrational numbers.
No - the sum of any two rational numbers is still rational:
Not necessarily. The sum of two irrational numbers can be rational or irrational.
It may be a rational or an irrational number.
Yes. The sum of two irrational numbers can be rational, or irrational.
Sqrt(2) and sqrt(3)
Since the sum of two rational numbers is rational, the answer will be the same as for the sum of an irrational and a single rational number. It is always irrational.
Yes
Not necessarily. 3+sqrt(2) and 3-sqrt(2) are both irrational numbers. Their sum is 6 - a rational.
Let R1 = rational number Let X = irrational number Assume R1 + X = (some rational number) We add -R1 to both sides, and we get: -R1 + x = (some irrational number) + (-R1), thus X = (SIR) + (-R1), which implies that X, an irrational number, is the sum of two rational numbers, which is a contradiction. Thus, the sum of a rational number and an irrational number is always irrational. (Proof by contradiction)