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It looks to me as if that's true. I reasoned thusly, and scratched it out

on the margin of my coffee-stained notepad:

You gave me integers separated by 2, so the integers are [x] and [x+2].

-- Their squares are [x2] and (x+2)2

-- That's [x2] and [x2 + 4x + 4].

-- The sum of their squares is [x2 + x2 + 4x + 4]

= [ 2x2 + 4x + 4 ]

-- Since [x] is an integer, each term in that trinomial is an integer.

-- The coefficients are '2' and '4', so each term is an even number.

-- So their sum is even.

-- Q.E.D.

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Q: Is the sum of the squares of integers separated by a value of 2 will always be even?
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