Let the number be x 12-2x = -7 -2x = -7-12 -2x = -19 x = 9.5
Let the number be x Twice a number means 2x 7 less than twice a number means 2x-7
Suppose n is the smaller integer. Since it is even, let n = 2x where x is an integer. Then the second integer is 2x+2 So 2x + 3*(2x+2) = 22 2x + 6x + 6 = 22 8x + 6 = 22 Subtract 6 from both sides: 8x = 16 Divide both sides by 4: 2x = 4 So the two integers are 2x and 2x+2 ie 4 and 6
(2x + 1)(x + 3) are the factors.
A.) j(a) = a^2 - 2a + 4 B.) j(3) = (3)^2 - 2(3) + 4 = 9 - 6 + 4 = 7 C.) j(x^2) = (x^2)^2 - 2(x^2) + 4 = x^4 - 2x^3 + 4 D.) j(x+3) = (x + 3)^2 - 2(x + 3) + 4 = x^2 +6x + 9 - 2x - 6 + 4 = x^2 + 4x + 7 E.) j(x+h) = (x + h)^2 - 2(x + h) + 4 = x^2 + 2hx + h^2 - 2x - 2h + 4
5
104
X = 7 9x - 2x = 49
X = 7 9x - 2x = 49
to divide
X = 6 5x + 2x = 42
Evaluate the expression below when x = 2.3x2-2x+4
Integrate by parts: ∫ uv dx = u ∫ v dx - ∫ (u' ∫ v dx) dx Let u = -2x Let v = cos 3x → u' = d/dx -2x = -2 → ∫ -2x cos 3x dx = -2x ∫ cos 3x dx - ∫ (-2 ∫ cos 3x dx) dx = -2x/3 sin 3x - ∫ -2/3 sin 3x dx = -2x/3 sin 3x - 2/9 cos 3x + c
Let y = ln (2x), let u = 2x. Then:dy/dx = dy/du * du/dx= 1/(2x) * 2= 1/x.
(2x - 9)(2x - 9)
1
-2x plus 3y equals 1