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What are two consecutive even integers such that the smaller added to 3 times the larger gives a sum of 22?
Wiki User
∙ 12y ago
Suppose n is the smaller integer.
Since it is even, let n = 2x where x is an integer.
Then the second integer is 2x+2
So 2x + 3*(2x+2) = 22
2x + 6x + 6 = 22
8x + 6 = 22
Subtract 6 from both sides: 8x = 16
Divide both sides by 4: 2x = 4
So the two integers are 2x and 2x+2 ie 4 and 6
Wiki User
∙ 12y ago
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When the smaller of two consecutive integers is added to two times the larger the result is 17 find the integers?
They are 5 and 6 because 5+(2*6) = 17
When the smaller of two consecutive integers is added to four times the larger the result is 59?
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
When the smaller of two consecutive integers is added to five times the larger the result is 41?
Suppose n is the smaller integer. Then the larger integer is n + 1, so that 5 times the larger is 5*(n + 1). Their sum is n + 5*(n + 1) = 6n + 5 Therefore 6n + 5 = 41 6n = 41 - 5 = 36 So that n = 36/6 = 6
When the smaller of two consecutive integers is added to two times the larger the result is 26 find the integers?
Let x represent the smaller of the two integers.Since integers are also members of the set of whole numbers, then the next largest consecutive integer must be (x+1)Translating the question into a mathematical equation:x + 2(x + 1) = 26x + 2x + 2 = 26add the "ex's"3x + 2 = 26subtract 2 from both sides of the equation3x = 24divide both sides of the equation by 3, to solve for xx = 8, and x + 1 = 9the solution is 8 and 9 [8 + (2*9)] = 26;; [8 + 18] = 26
Find two consecutive even integers such that the smaller added to two times the larger gives a sum of 16?
4+(6+6) All these words in mathematics are represented by an equation. Write and solve it to find those integers. If the first integer is x, the second one will be x + 2 (since consecutive even integers differ by 2). So we have: x + 2(x +2) = 16 x + 2x + 4 = 16 3x + 4 = 16 subtract 4 from both sides 3x = 12 divide by 3 both sides x = 4 Thus the integers are 4 and 6.
What are two consecutive integers such that the smaller added to two times the larger gives a sum of 16?
There are no such integers.
When the smaller of two consecutive integers is added to three times the larger the result is 51. Find the integers?
12 and 13.
When the smaller of two consecutive integers is added to five times the larger the result is 65?
The integers are 10 and 11.
Find two consecutive even integers such that the smaller added to four times the larger gives a sum of 58?
10,12
When the smaller of two consecutive integers is added to two times the larger the result is 17 find the integers?
They are 5 and 6 because 5+(2*6) = 17
When the smaller of two consecutive integers is added to four times the larger the result is 59?
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
When the smaller of two consecutive integers is added to five times the larger the result is 53. Find the integers?
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
What are two consecutive odd integers that when twice the larger is added to the small the result is 169?
55 and 57
When the smaller of two integers is added to three times the larger the result is 51. Find the integers?
12 and 13.
When the smaller of two consecutive integers is added to five times the larger the result is 53 find the integers?
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
When the smaller of two consecutive integers is added to three times the larger result is 23?
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6
When the smaller of two consecutive integers is added to three times the larger the result is 43 find the integers?
Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.
