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The prime numbers between 8 and 25 are: 11 13 17 19 and 23
7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.
There are 8 prime numbers between 1 and 20. The numbers are 2, 3, 5, 7, 11, 13, 17, and 19.