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Q: Prime numbers between 8 and 56?

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less than 100

The prime numbers between 8 and 25 are: 11 13 17 19 and 23

7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.

The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.

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less than 100

56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers

1, 2, 4, 7, 8, 14, 28, 56 2 and 7 are prime.

To get the gcf of 56 and 48, you have to split the numbers into their prime factors: 56 = 2x2x2x7 48 = 2x2x2x2x3 Next you have to spot any common prime factors. In this case both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 And so the GCF of 56 and 48 is 8.

The prime numbers between 8 and 25 are: 11 13 17 19 and 23

Yes it can be divided by 1,7 and 8

There are 5 prime numbers between 8 and 28: 11 13 17 19 23

Prime factors of 56 First, what two numbers multiplied give you 56? 7 x 8 Is either of these a prime number?? Yes, 7 is prime. What about 8? What two numbers multiplied together give you 8? 2 x 4 Is either of these a prime number?? Yes, 2 is prime. What about 4? What two numbers multiplied together give you 4? 2 x 2 Is either of these a prime number?? Yes, both are prime. Combining our individual results, the prime factorisation of 56 is 7 x 2 x 2 x 2

One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...

LCM is 56, which is the multiple of the highest power of prime factors in the given numbers (23 x 7).

56 is 8*7

7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.

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