One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...
The numbers are 15, 9, and 3.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
15 and 3
The numbers are: 3 and 12
If you mean the numbers are all 15 then the answer is 45 otherwise the answer is the 15 that you already stated in your question to be the sum.
The numbers are 15, 9, and 3.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
15 and 3
The numbers are: 3 and 12
Zero and 15.
15
Their sum is 15.
If you mean the numbers are all 15 then the answer is 45 otherwise the answer is the 15 that you already stated in your question to be the sum.
The numbers are 15 and 3. 15 * 3 = 45 15 + 3 = 18
127
3 & 15
The two numbers are 8 and 15