One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...
The numbers are 15, 9, and 3.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
15 and 3
The numbers are 15 and 3. 15 * 3 = 45 15 + 3 = 18
3 & 15
The numbers are 15, 9, and 3.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
15 and 3
Zero and 15.
15
Their sum is 15.
The numbers are 15 and 3. 15 * 3 = 45 15 + 3 = 18
3 & 15
3 and 12
12 and 3
The two numbers are 8 and 15
six, nine 9 + 6 = 15 (sum) 9 - 6 = 3 (difference) 9 x 6 = 54 (product)