293 is already prime; no need for a factorization.
There is no factorization of 293 because 293 is a prime number. It is divisible only by 1 and itself.
The prime factorization is... 2x2x2x2x2x5x5
Yes. Any prime number greater than 100 has only itself in its prime factorization. Examples: The prime factorization of 101 is 101. The prime factorization of 109 is 109. The prime factorization of 127 is 127. The prime factorization of 311 is 311. The prime factorization of 691 is 691.
The prime number is the prime factorization. For example, the prime factorization of the prime number 3 is 3. Get it?
293 is already prime.
293 is already prime; no need for a factorization.
The positive integer factors of 293 are: 1, 293
N/A - 293 is a prime number.
None. 293 is a prime number.
It is itself because 293 is a prime number
293 is a prime number. so factors are 1 x 293
293 is a prime number, therefore the prime factorization of it would be 293, you cant do 293x1 because 1 is NOT a prime number therefore you cant do it because it wouldn't b a prime factorization that is your answer
It is simply 293 because it is a prime number in its own right
293 is a prime number
293 is already prime. No tree.
The factors of 292 are 1 2 4 73 146 and 292