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How do you rewrite 9x 4(2x 20) using distributive property?
To rewrite ( 9x + 4(2x + 20) ) using the distributive property, you first distribute the ( 4 ) across the terms inside the parentheses. This results in ( 9x + 4 \cdot 2x + 4 \cdot 20 ), which simplifies to ( 9x + 8x + 80 ). Finally, you can combine the like terms ( 9x ) and ( 8x ) to get ( 17x + 80 ).
How do i rewrite 3(4 5) using distributive property?
To rewrite (3(4 + 5)) using the distributive property, you distribute the 3 to both terms inside the parentheses. This means you multiply 3 by 4 and 3 by 5: [ 3(4 + 5) = 3 \cdot 4 + 3 \cdot 5 = 12 + 15. ] So, (3(4 + 5) = 12 + 15).
How do you rewrite 40 16 using the distributive property and a common factor?
(5 x 8) + (2 x 8) = 7 x 8 = 56
Can you find the greatest common factor of the numbers 12 and 18 and rewrite the sum using the distributive property?
(6 x 2) + (6 x 3) = 6 x 5 = 30
What is 7 multiplied by 14 look like when using distributive property?
7*14 = 98. Why does the distributive property need to come into it?
How do you rewrite 2f 10 by using distributive property?
2f + 10 in distributive property
What property was use to rewrite 9x2plus9x3?
The property used to rewrite 9x2 + 9x3 is the Distributive Property. Using the Distributive Property the expression can be rewritten as 9x2 + 9x2 + 9x2 or 27x2.
What is the GCF of 10w and 5w?
5w
How do you rewrite the problem 607x20 using the distributive property?
607*20 = 600*20 + 7*20
How do you simplify 108 times 210 using the distributive property?
22680 is the answer
How do you rewrite 2(n plus 2n) using the distributive property?
To rewrite ( 2(n + 2n) ) using the distributive property, you distribute the 2 across the terms inside the parentheses. This gives you ( 2 \cdot n + 2 \cdot 2n ), which simplifies to ( 2n + 4n ). Finally, you can combine like terms to get ( 6n ). Thus, ( 2(n + 2n) = 6n ).
How can you find 37 times 9 using the distributive property?
OWO
How do you rewrite 48 plus 60 using the distributive property?
(4 x 12) + (5 x 12) = 9 x 12 = 108
How do i rewrite 3(4 5) using distributive property?
To rewrite (3(4 + 5)) using the distributive property, you distribute the 3 to both terms inside the parentheses. This means you multiply 3 by 4 and 3 by 5: [ 3(4 + 5) = 3 \cdot 4 + 3 \cdot 5 = 12 + 15. ] So, (3(4 + 5) = 12 + 15).
How do you rewrite 9x 4(2x 20) using distributive property?
To rewrite ( 9x + 4(2x + 20) ) using the distributive property, you first distribute the ( 4 ) across the terms inside the parentheses. This results in ( 9x + 4 \cdot 2x + 4 \cdot 20 ), which simplifies to ( 9x + 8x + 80 ). Finally, you can combine the like terms ( 9x ) and ( 8x ) to get ( 17x + 80 ).
How do you write 364 x 26 in distributive property?
To express ( 364 \times 26 ) using the distributive property, you can break down 26 into smaller parts, like 20 and 6. This gives you: [ 364 \times 26 = 364 \times (20 + 6) ] Using the distributive property, this expands to: [ 364 \times 20 + 364 \times 6 ] Now you can calculate each part separately.
What is the distributive property for 4 times 15?
The distributive property states that when you multiply a number by a sum, you can distribute the multiplication to each addend. For example, 4 times 15 can be expressed as 4 times (10 + 5). Using the distributive property, this equals 4 times 10 plus 4 times 5, which is 40 + 20, resulting in 60.
