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How do i rewrite 3(4 5) using distributive property?
To rewrite (3(4 + 5)) using the distributive property, you distribute the 3 to both terms inside the parentheses. This means you multiply 3 by 4 and 3 by 5: [ 3(4 + 5) = 3 \cdot 4 + 3 \cdot 5 = 12 + 15. ] So, (3(4 + 5) = 12 + 15).
How do you rewrite 9x 4(2x 20) using distributive property?
To rewrite ( 9x + 4(2x + 20) ) using the distributive property, you first distribute the ( 4 ) across the terms inside the parentheses. This results in ( 9x + 4 \cdot 2x + 4 \cdot 20 ), which simplifies to ( 9x + 8x + 80 ). Finally, you can combine the like terms ( 9x ) and ( 8x ) to get ( 17x + 80 ).
How do you rewrite 40 16 using the distributive property and a common factor?
(5 x 8) + (2 x 8) = 7 x 8 = 56
Can you find the greatest common factor of the numbers 12 and 18 and rewrite the sum using the distributive property?
(6 x 2) + (6 x 3) = 6 x 5 = 30
What is 7 multiplied by 14 look like when using distributive property?
7*14 = 98. Why does the distributive property need to come into it?
How do you rewrite 2f 10 by using distributive property?
2f + 10 in distributive property
What property was use to rewrite 9x2plus9x3?
The property used to rewrite 9x2 + 9x3 is the Distributive Property. Using the Distributive Property the expression can be rewritten as 9x2 + 9x2 + 9x2 or 27x2.
What is the GCF of 10w and 5w?
5w
How do you rewrite the problem 607x20 using the distributive property?
607*20 = 600*20 + 7*20
How do you simplify 108 times 210 using the distributive property?
22680 is the answer
How do you rewrite 2(n plus 2n) using the distributive property?
To rewrite ( 2(n + 2n) ) using the distributive property, you distribute the 2 across the terms inside the parentheses. This gives you ( 2 \cdot n + 2 \cdot 2n ), which simplifies to ( 2n + 4n ). Finally, you can combine like terms to get ( 6n ). Thus, ( 2(n + 2n) = 6n ).
How can you find 37 times 9 using the distributive property?
OWO
How do you rewrite 48 plus 60 using the distributive property?
(4 x 12) + (5 x 12) = 9 x 12 = 108
How do i rewrite 3(4 5) using distributive property?
To rewrite (3(4 + 5)) using the distributive property, you distribute the 3 to both terms inside the parentheses. This means you multiply 3 by 4 and 3 by 5: [ 3(4 + 5) = 3 \cdot 4 + 3 \cdot 5 = 12 + 15. ] So, (3(4 + 5) = 12 + 15).
How could you use the distributive property to show 84 divided by 7?
12
How do you rewrite 40 16 using the distributive property and a common factor?
(5 x 8) + (2 x 8) = 7 x 8 = 56
What is an expression using the distributive property to find the product of 7x63?
To find the product of 7 and 63 using the distributive property, you can break down 63 into more manageable parts. For example, you can express 63 as 60 + 3. Then, apply the distributive property: (7 \times 63 = 7 \times (60 + 3) = 7 \times 60 + 7 \times 3). This simplifies to (420 + 21), which equals 441.
