17.
Chat with our AI personalities
no, the square root of an integer will not always be another integer. take the integer 27, for example. the square root of 27 is about 5.1961, which is not an integer.No eg square root of 17 is 4.1231056...
Only integers are even or odd. If a decimal is equal to an integer (for example 24.0 is equal to 24), then it can be even or odd. If a decimal is not equal to an integer (for example, 24.1 is not an integer), then it is neither even nor odd.
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
Some sources say that the answer is no because a negative integer is less than zero and a positive integer is greater that zero. This answer is partially incorrect because if a negative integer is in an absolute value problem, it can potentially be greater that a positive integer. Example: |-11| > 7 because |-11|=11 because it is in an absolute value problem. Simplified, the problem is 11 > 7 So yes, in some cases a negative integer is greater that a positive integer.
1/2, 5, pi, respectively