Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3.
then x2 = 3*a which is divisible by 3.
but x is not even rational and so is not an integer and is certainly not divisible by 3.
2520
That means that if you perform a division sum with the number and its factor, the result would be an integer. For example, 15 is divisible by 1, 3, 5 and 15. 15/3 = 5, 15/5 = 3.
what os the set of all integers divisible by 5
Numbers that are divisible by 1024 are multiples of 1024, meaning they can be expressed as 1024 times an integer. In other words, any number that can be written as 1024 x n, where n is an integer, is divisible by 1024. Some examples of numbers divisible by 1024 are 1024, 2048, 3072, and so on.
14 of them.
The statement is not true. Disprove by counter-example: 3 is an integer and 5 is an integer, their product is 15 which is odd.
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
Yes, but you wont get an integer. 120 and 135 are divisible to an integer.
An even integer
If an integer's square is divisible by four, then it is even.
No, not always. For example: 55 divided by 5 is 11. 55 divided by 10 is 5.5. It will divide, but not to an integer.
An integer is odd if and only if it is not divisible by two.
When you divide a number by 1, it remains the same. A number is considered divisible is the resulting answer is an integer with no remainder left over. Thus, if the starting number is an integer, it will be divisible by 1. 15345 is an integer, and thus is divisible by 1.
For an integer x to be evenly divisible by another integer y, x/y must also be an integer. Here are some examples: 4/2=2. 15/3=5. 18/6=3. From these examples, you can see that 4 is divisible by 2, 15 is divisible by 3, and 18 is divisible by 6. When two numbers are not evenly divisible by each other, you end up with a remainder, or fractional/decimal answer. Here is an example: 25/2 =12.5
111 is the least positive integer divisible by 111 without remainder.
There are no integer palindromes between 1,000 and 9,000 that are divisible by 20.
10