answersLogoWhite

0

True

Observe the following:

5x + 5y + 3z = 5(x + y) + 3z

The first two terms could be factored because they shared a common factor of 5, but the third term did not -- not all terms need to share a common factor to use the grouping method.

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

What is another name for factoring by grouping?

Another name for factoring by grouping is the "method of grouping." This technique involves rearranging and grouping terms in a polynomial to factor it into a product of simpler expressions. It is particularly useful for polynomials with four or more terms.


What is the step of factorising by grouping?

Factorising by grouping involves rearranging and grouping terms in a polynomial to factor out common factors. First, you split the polynomial into two groups, then factor out the greatest common factor from each group. If done correctly, these groups will have a common binomial factor, which can then be factored out, resulting in a simplified expression. This method is particularly useful for polynomials with four terms.


What are the three methods of factoring?

1. Factoring out a common monomial 2. Factoring out the differnece of two perfect square numbers 3. Factoring out a common binomial


What is the first factoring method you should always try?

The first factoring method you should always try is the greatest common factor (GCF). By identifying and factoring out the GCF from all terms in an expression, you simplify the problem and often make it easier to see further factoring opportunities. This method not only reduces the expression but also sets a solid foundation for applying other factoring techniques if needed.


What are the different factoring methods?

There are several factoring methods, including: Greatest Common Factor (GCF): This involves finding the largest factor shared by all terms in a polynomial. Grouping: This method groups terms with common factors and factors them separately. Difference of Squares: This applies when a polynomial can be expressed as the difference between two squares, allowing for the use of the formula (a^2 - b^2 = (a - b)(a + b)). Quadratic Trinomials: This method factors trinomials of the form (ax^2 + bx + c) into binomials, often using techniques like trial and error or the quadratic formula.


How do you factor ab plus 3a-2b-6?

(a - 2)(b + 3)


Could you factor the polynomial 3ax-15a plus x-5?

Do you mean (3ax-15a)+(x-5)?If so, then this is simply a matter of factoring by grouping, which you should have learned in pre-algebra.You should show these steps in your work:1. (3ax-15a)+(x-5)- beginning equation2. 3a(x-5)+1(x-5)- factoring it out3. (3a+1)(x-5)- rule of factoring by groupingYou should learn this method, because it is very simple and helps you a lot in factoring chapters.


When you are factoring a trinomial with a leading coefficient other than 1 which would be the best thing to do first?

When factoring a trinomial with a leading coefficient other than 1, the best first step is to look for two numbers that multiply to the product of the leading coefficient and the constant term while also adding up to the middle coefficient. This method is often referred to as the "AC method." Once these numbers are found, you can rewrite the middle term as a sum of two terms and then factor by grouping.


What is the greatest common factor of 43 and 128?

The greatest common factor for 43 and 32 is 1. Method 1: Factoring completely, we determine that: 32 = 2 * 2 * 2 * 2 * 2 * 1 43 = 43 * 1 The only factor that these two have in common is 1, making this the greatest common factor. Method 2: We notice that 32 is a power of 2 (2 ^ 5, to be exact), so its only unique factors are 1 and 2. Since 43 is odd, it does not have 2 as a factor. Therefore, the only factor that they could have in common is 1, making that the greatest common factor. Method 3: We notice that 43 is a prime number, meaning that its only factors are 1 and itself. Since 32 is not a multiple of 43 (impossible, being smaller), the only common factor they could have is 1.


what makes 88 addition?

True Observe the following: 5x + 5y + 3z = 5(x + y) + 3z The first two terms could be factored because they shared a common factor of 5, but the third term did not -- not all terms need to share a common factor to use the grouping method


How can you use the grouping method to solve the equation 6x2 - 11x?

To use the grouping method to solve the equation (6x^2 - 11x = 0), first factor out the common term (x): (x(6x - 11) = 0). This gives us two factors: (x = 0) and (6x - 11 = 0). Solving the second factor, we get (6x = 11) or (x = \frac{11}{6}). Thus, the solutions are (x = 0) and (x = \frac{11}{6}).


-4p+(-2)+2p+3?

True Observe the following: 5x + 5y + 3z = 5(x + y) + 3z The first two terms could be factored because they shared a common factor of 5, but the third term did not -- not all terms need to share a common factor to use the grouping method.