Answer : 24 and 25 (24 x 25 = 600)
Let the two numbers be represented by n and n + 1.
n(n + 1) = 600 : n2 + n - 600 = 0
This equation can be factored (n + 25) (n - 24) = 0
As we only require the positive number solution then this occurs when n - 24 = 0, n = 24.
As n = 24 then n + 1 = 25
It is 0.7*600 = 420
The smallest number that is 600 when rounded to the nearest hundred is 550. The largest number that is 600 when rounded to the nearest hundred is 649.
600 x 500 = 300000 612 x 490 = 299880
600% = 6, a whole number
There are an infinite amount of numbers that will round to 600.
The numbers are 24 and 25.
The numbers are 24 and 25.
25 and 26
24 and 25 or -25 and -24
The sum of the first 600 consecutive odd numbers is 360,000.
The sum of consecutive integers will always be odd. Consecutive odd numbers will be even. 299 + 301 = 600
They are consecutive odd numbers: 299 and 301.
24 and 25 are consecutive numbers that are factors of 600.
600
Let x = first number x + 1 = next consecutive number x ( x + 1) = 600 X^2 + x -600 = 0 factor: (X-24) (x +25) = 0 X = 24 Answer: 24,25
10x60, 1x600
There are none. However there are two consecutive ODD numbers 299 and 301