Q: The reciprocal of two times a certains integer plus the reciprocal of 2 more than twice the integer equals 724 what is the integer?

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A negative integer. Every time.

1/x + 1/2x + 2 = 2/3; 3/2x = -4/3; -8x = 9 (2 + 1)/2x + 2 = 2/3 3 + 4x = 4x/3 9 + 12x = 4x 8x = -9 x = -1 1/8 which isn't an integer but fits the stated conditions If you're doing A+ the answer is 2.

Then, if the exponent is a positive integer, the value is 1 multiplied by the base repeatedly, exponent times. If the exponent is a negative integer then it is the reciprocal of the above value.In either case, it is NOT the base multiplied by itself an exponent number of times.

Yes. The square of an integer is just the number times itself. For any two whole numbers that are multiplied, the answer is always an integer (i.e. no decimals).

-60

Related questions

2

It is 2.

9

80

This question can be expressed algebraically as: (1/n) + (1/(2n)) + 2 = 23, (1/n) + (1/(2n)) =21, ((1+2)/(2n)) = 21, (3/(2n)) = 21, or 2n = (3/21), 2n = (1/7), so n = (1/14). This, by the way, is an elementary algebraic proof that the solution to the above relation is (1/14). Anyway, to answer the question, reread the question: "[What integer is such that] the reciprocal of the integer...". notice, the reciprocal of (1/14) is 14, which is the integer in question! ^_^

4

A negative integer. Every time.

Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9

1/2n + 1/(2n+2) = 1/2*[(1/n + 1/(n+1)] = 1/2*(2n+1)/[n*(n+1)] or (2n+1)/[2*n*(n+1)]

4

The equasion would be 10x 1/j = 5x1/9 (if j equals some number) so the answer would be j=18.

That has no integer solution. Three times an integer is another integer; if you subtract to integers, you get an integer again, not a fraction.