5 and 8
The product of all of the factors of 40 is (1, 2, 4, 5, 8, 10, 20, 40) : 2,560,000
You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5)
20 and 20.
2 x 2 x 2 x 5 = 40
36
8 and 5
8 and 5
The anwer is 8 and 5 and thedifference of the two is 3
When the product of 15 and 40 is divided by the sum of 15 and 45, what is the quotient?
368
40 20,2 10,2,2 5,2,2,2 2 x 2 x 2 x 5 = 40
The product of all of the factors of 40 is (1, 2, 4, 5, 8, 10, 20, 40) : 2,560,000
20+20=40 20x20=400
5(8 + 5)
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
As a product of its prime factors: 2 * 2 * 2 * 5 = 40 As a product of its prime factors: 2 * 2 * 5 * 5 = 100
You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5)