Q: What 2 factors have a product of 40 and a sum of 13?

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The product of all of the factors of 40 is (1, 2, 4, 5, 8, 10, 20, 40) : 2,560,000

You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5)

20 and 20.

2 x 2 x 2 x 5 = 40

36

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8 and 5

8 and 5

The anwer is 8 and 5 and thedifference of the two is 3

When the product of 15 and 40 is divided by the sum of 15 and 45, what is the quotient?

368

40 20,2 10,2,2 5,2,2,2 2 x 2 x 2 x 5 = 40

20+20=40 20x20=400

The product of all of the factors of 40 is (1, 2, 4, 5, 8, 10, 20, 40) : 2,560,000

5(8 + 5)

1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75

You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5)

As a product of its prime factors: 2 * 2 * 2 * 5 = 40 As a product of its prime factors: 2 * 2 * 5 * 5 = 100