Best Answer

1/x + 1/y = (y+x)/xy

But y + x = sum = 150, and xy = product = 40

So sum of reciprocals = 150/40 = 3.75

Q: Find the sum of the reciprocals of two real numbers given that these numbers have a sum of 150 and a product of 40?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

Two numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.

The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.

The product of two consecutive even integers is 840.find these numbers

if the product of two numbers is 810 if there hcf is 9 find Lcm

A product cannot exist of a single number - a product is formed by multiplying two separate numbers.

Related questions

Two numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.

If by "opposite" you mean "additive inverse", then yes.

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.

x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv

The product of two consecutive even integers is 840.find these numbers

if the product of two numbers is 810 if there hcf is 9 find Lcm

You need at least two numbers to find a product.

Two or more numbers are needed to find their product

Factor

It is a positive.

A product cannot exist of a single number - a product is formed by multiplying two separate numbers.