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∙ 13y ago1/x + 1/y = (y+x)/xy
But y + x = sum = 150, and xy = product = 40
So sum of reciprocals = 150/40 = 3.75
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∙ 13y agoTwo numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.
The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.
The product of two consecutive even integers is 840.find these numbers
if the product of two numbers is 810 if there hcf is 9 find Lcm
A product cannot exist of a single number - a product is formed by multiplying two separate numbers.
Two numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.
If by "opposite" you mean "additive inverse", then yes.
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.
x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv
The product of two consecutive even integers is 840.find these numbers
if the product of two numbers is 810 if there hcf is 9 find Lcm
You need at least two numbers to find a product.
Two or more numbers are needed to find their product
Factor
It is a positive.
A product cannot exist of a single number - a product is formed by multiplying two separate numbers.