Two numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.
To find the product of the reciprocals of the fractions 9/16 and -11/18, we first find the reciprocals of each fraction. The reciprocal of 9/16 is 16/9, and the reciprocal of -11/18 is -18/11. Next, we multiply these reciprocals together: (16/9) * (-18/11) = -288/99. Finally, we simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 9, resulting in the final product of -32/11.
The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.
if the product of two numbers is 810 if there hcf is 9 find Lcm
A product cannot exist of a single number - a product is formed by multiplying two separate numbers.
Two numbers with a product of 1 are called reciprocals. If you have a number and want to find the reciprocal of it, simply divide 1 by the number. For example, the reciprocal of 5 is 1/5, and the reciprocal of 700 is 1/700.
If by "opposite" you mean "additive inverse", then yes.
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
To find the product of the reciprocals of the fractions 9/16 and -11/18, we first find the reciprocals of each fraction. The reciprocal of 9/16 is 16/9, and the reciprocal of -11/18 is -18/11. Next, we multiply these reciprocals together: (16/9) * (-18/11) = -288/99. Finally, we simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 9, resulting in the final product of -32/11.
The product of the original numbers is equal to the product of the GCF and LCM. Divide the product of the LCM and GCF by the one number. The answer will be the other.
x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv
if the product of two numbers is 810 if there hcf is 9 find Lcm
You need at least two numbers to find a product.
Two or more numbers are needed to find their product
Let the page numbers be x and x+1. The product of two consecutive numbers is x(x+1). Given that the product is 4160, we have the equation x(x+1) = 4160. By solving this quadratic equation, we find that the page numbers are 64 and 65.
Let's denote the two consecutive numbers as x and x+1. The product of two consecutive numbers is given by x(x+1). We are given that x(x+1) = 6162. By solving this equation, we find that x = 78. Therefore, the two consecutive numbers are 78 and 79, as 78 * 79 = 6162.
It is a positive.