64 and 1, 32 and 2, 16 and 4, 8 and 8, .
2 x 2 x 2 x 8 2 x 2 x 4 x 4
These are the pairs of numbers that when multiplied are equal to 64: (1, 64) (2, 32) (4, 16) (8, 8)
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
The only prime factor of 64 is 2.
64 has only one prime factor and it is 2
4*4*2*2
How about: 8*4*2 = 64
The factors of 64 are 1, 2, 4, 8, 16, 32, and 64 .
128
8 and 8 or 4 and 16 or 2 and 32
The answer is 8
192
8
1.) Multiply 2 times 64 2*64=128 Then take the first number and multiply it by 10, 1*10=10 2.)Take the new number and multiply it by 64 10*64=640 3.) add the two new numbers together 128+640=768 (*)=times 64 12* 128 640+ 768
Well first use divide each by prime numbers such as 2, 3, 5 that will work, until you have 1 left.64/2=32 2/2=132/2=1616/2=88/2=44/2=22/2=1Then you take the numbers you divide by(the prime numbers) and multiply them.64 22*2*2*2*2*2 2Then find the numbers that both LCM numbers have in common(64 and 2)In this case it is the number(2*2*2*2*2*2) *(2)The bold ones cancel out only one of them not both.So now you take the rest of the numbers and multiply them.2*2*2*2*2*2=64The LCM is 64
64
1 x 64, 2 x 32, 4 x 16, 8 x 8.