1.5, 3 and 4.5 is one possible answer.
But if the numbers are restricted to integers,
then there are two better sets that answer the same question:
1, 4 and 4; also, 2, 2 and 5.
Well, isn't that just a happy little math problem! To find three numbers that fit these criteria, we can start by placing the median number in the middle, which is 3. Since the mean is also 3, the sum of all three numbers must be 9. By considering the range of 3, we can choose numbers like 2, 3, and 4. This way, we have a mean of 3, a median of 3, and a range of 3. Just like painting, math can be a beautiful and creative process!
All the numbers in that range that end with 1, 3, 5, 7, or 9.
2 and 3 are the only consecutive prime numbers.
If all the numbers are the same, the set has no range. The range is zero.
If you mean: 2 3 5 7 11 13 then they are all prime numbers
The numbers 3, 5, and 7 together have a range of 4 and a mean of 5.
{4,6,8}
{1.5, 3, 4.5}
To find four numbers with a range of 6, a mean of 4, and a median of 3, we can start by setting up an equation for the mean. The mean is the sum of all numbers divided by the total number of values. So, 4 = (a + b + c + d) / 4, where a, b, c, and d are the numbers. Since the median is 3, the two middle numbers must be 3 and 3. The range is the difference between the maximum and minimum values, so the numbers could be 0, 3, 3, and 6.
-2, 0, 1, 3, 3.
Add them all together, then divide by the number of the amount of numbers. Say you wanted the mean of 2, 3, and 4. You would add 2, 3, and 4 then divide by 3, because there are 3 numbers.
Well, isn't that just a happy little math problem! To find three numbers that fit these criteria, we can start by placing the median number in the middle, which is 3. Since the mean is also 3, the sum of all three numbers must be 9. By considering the range of 3, we can choose numbers like 2, 3, and 4. This way, we have a mean of 3, a median of 3, and a range of 3. Just like painting, math can be a beautiful and creative process!
(10, 12, 12, 13, 13)
6, 7 and 20.
1, 4, 10
(3, 4, 6, 8, 9)
3, 3, 5, 9, 10