As a product of its prime factors: 2*2*3*5 = 60
60/4 and 60 x 4. Answer, 60 and 4
To find three consecutive numbers that multiply to 60, you can start by estimating the cube root of 60, which is about 3.9. The three consecutive integers around this value are 3, 4, and 5. Multiplying these together: (3 \times 4 \times 5 = 60). Thus, the three consecutive numbers are 3, 4, and 5.
3 x 4 x 5 = 60 The three consecutive numbers are 3, 4, and 5.
I can find 13 ways, not just 7, to make 60 from adding numbers in the 4, 5 and 9 times tables.
60 and 30
30 and 4
The two numbers you are looking for are 6 and 10. When multiplied, 6 × 10 equals 60, and when added, 6 + 10 equals 16, not 4. However, if you are looking for numbers that multiply to 60 and add to 4, those numbers do not exist in the realm of real numbers.
The two numbers you are looking for are -15 and 4. When you multiply -15 and 4, you get -60, and when you add them together, you get -13.
8 x 8 60 + 4 70 - 6 128/2
The GCF is 4.
1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12, 6 x 10 = 60
The LCM of the given three numbers is 60